Question

我正在尝试解析地址，以便可以检索地址，地址编号和地址字母。

string address = "Mushroom road 2b";

我正在尝试

var addressName = "Mushroom Road";
var addressNumber = "2";
var addressLetter = "b";

我尝试使用split并使用子字符串对其进行解析。

   string adress = "Mushroom road 2b";
   string temp = adress;

   var res = temp.Substring(temp.IndexOf(' '));
   //check if res first letter = number?
   //Not sure how to use regex really
   var addressNumber = Regex.Replace(temp, @"[^\d]", "");

RES将是2b路。但是我想先检索蘑菇道，然后检索2，然后检索b。

Answer 1

您可以尝试正则表达式，例如：

  using System.Text.RegularExpressions;

  ...

  var match = Regex.Match(
      source, 
    @"(?<street>[A-Z][A-Za-z'\s]*)(?<number>[0-9]+)\s*(?<letter>[a-zA-Z]*)"); 

  if (match.Success) {
    // "Mushroom Road"
    var addressStreet = match.Groups["street"].Value.Trim(); 
    // "2"
    var addressNumber = match.Groups["number"].Value;
    // "b"
    var addressLetter = match.Groups["letter"].Value; 
    ...
  }

模式(?<street>[A-Z][A-Za-z'\s]*)(?<number>[0-9]+)\s*(?<letter>[a-zA-Z]*)的意思是

  (?<street>[A-Z][A-Za-z'\s]*) one capital letter A..Z followed by 
                               zero or more letters (a..z A..Z), 
                               apostrophes and whitespaces  
  (?<number>[0-9]+)            one or more digits
  \s*                          zero or more whitespaces  
  (?<letter>[a-zA-Z]*)         zero or more letters a..z A..Z

演示：

string[] tests = new string[] {
  "Mushroom road 2b",
  "Mushroom road 2 b",
  "Mushroom 2"
};

var results = tests
  .Select(test => new {
    test,
    match = Regex.Match(
        test,
      @"(?<street>[A-Z][A-Za-z'\s]*)(?<number>[0-9]+)\s*(?<letter>[a-zA-Z]*)")
  })
  .Select(item => new {
    test = item.test,
    street = item.match.Groups["street"].Value.Trim(),
    number = item.match.Groups["number"].Value,
    letter = item.match.Groups["letter"].Value
  })
  .Select(item => 
     $"{item.test,-20} => \"{item.street}\"; \"{item.number}\"; \"{item.letter}\"");

string report = string.Join(Environment.NewLine, results);

Console.Write(report);

结果：

Mushroom road 2b     => "Mushroom road"; "2"; "b"
Mushroom road 2 b    => "Mushroom road"; "2"; "b"
Mushroom 2           => "Mushroom"; "2"; ""

Answer 2

这可能已经晚了，但这是我不使用Regex的解决方案。

string address = "Mushroom road 2b";
var helpvar = "";
// Getting the last character and saving it
helpvar = address.Remove(0, address.Length -1);

// Removing the last character
address = address.Remove(address.Length - 1);

// String interpolation output
// Adding the string without last character
// Adding the last character , because we want them sperated
Console.Write($"{address} {helpvar}");

Answer 3

Split方法可能有用。

var parts = address.Split(' ');
addressName = parts[0];
addressNumber = parts[1];
addressLetter = parts[2];

或将正则表达式与组配合使用。

误读。

您现在可以使用parts [2]并使用.Substring。

您还可以迭代所有字符并对其进行测试。 Char类有一些有用的方法。

从字符串中检索空格后的数字

3 个答案: