Question

我正在尝试设置从https://css-tricks.com/building-a-simple-quiz/#comments获得的表单，以便如果所有答案均不正确，则会在结果中添加“失败”，并提供一个按钮以重试。但是，如果所有答案都是正确的，则会显示“通过”和一个继续进入新页面的按钮

虽然我承认我不擅长编码和脚本编写，但我尝试仅通过链接更改回显，但这并没有为我要查找的每个结果提供不同的显示。他们几乎必须正确回答所有答案才能前进，或者可以重试。

这是我正在使用的代码

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">

<head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />

    <title>PHP Quiz</title>

    <link rel="stylesheet" type="text/css" href="css/style.css" />
</head>

<body>

    <div id="page-wrap">

        <h1>Final Quiz for Lip building</h1>

        <?php

            $answer1 = $_POST['question-1-answers'];
            $answer2 = $_POST['question-2-answers'];
            $answer3 = $_POST['question-3-answers'];
            $answer4 = $_POST['question-4-answers'];
            $answer5 = $_POST['question-5-answers'];

            $totalCorrect = 0;

            if ($answer1 == "B") { $totalCorrect++; }
            if ($answer2 == "A") { $totalCorrect++; }
            if ($answer3 == "C") { $totalCorrect++; }
            if ($answer4 == "D") { $totalCorrect++; }
            if ($answer5) { $totalCorrect++; }

            echo "<div id='results'>$totalCorrect / 5 correct</div>";

        ?>

    </div>

    <script type="text/javascript">
    var gaJsHost = (("https:" == document.location.protocol) ? "https://ssl." : "http://www.");
    document.write(unescape("%3Cscript src='" + gaJsHost + "google-analytics.com/ga.js' type='text/javascript'%3E%3C/script%3E"));
    </script>
    <script type="text/javascript">
    var pageTracker = _gat._getTracker("UA-68528-29");
    pageTracker._initData();
    pageTracker._trackPageview();
    </script>

</body>

</html>

________
AND the PHP (grade.php) file
________


<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body bgcolor="#FFFFFF">



<?php

    $answer1 = $_POST['question-1-answers'];
    $answer2 = $_POST['question-2-answers'];
    $answer3 = $_POST['question-3-answers'];
    $answer4 = $_POST['question-4-answers'];
    $answer5 = $_POST['question-5-answers'];

    $totalCorrect = 0;

    if ($answer1 == "B") { $totalCorrect++; }
    if ($answer2 == "A") { $totalCorrect++; }
    if ($answer3 == "C") { $totalCorrect++; }
    if ($answer4 == "D") { $totalCorrect++; }
    if ($answer5) { $totalCorrect++; }

    echo "<div id='results'>$totalCorrect / 5 correct</div>";

?>





</body>
</html>

没有得到任何错误

Answer 1

简单的if语句就能解决问题

您可以在此行下的grade.php中添加此更改

 echo "<div id='results'>$totalCorrect / 5 correct</div>";

通过检查用户获得的分数来检查用户是否通过了测试

if($totalCorrect == 5){
    echo "<div id='results'>Pass</div>";
    echo '<button type="button" href="redirect.php">Click Me!</button>';

} else {
    echo "<div id='results'>Fail</div>";
}

重定向为PHP测验表格

1 个答案: