Question

我有一个包含大量目录的文件夹。我希望以字符串形式返回其中没有更多目录的每个文件夹的路径

示例目录结构

session_start();
require_once __DIR__ . './db_con_marco.php'; 

if (!isset($_SESSION['userSession'])) {
    $msg ="WARNING";
    header("Location: ../index.php?errorMessage=" . $msg);
    exit;   }


$queryText =  "
        SELECT * 
        FROM account
        WHERE BINARY username = '" . $_SESSION['userSession'] . "' ";

$query = $dbCon->query($queryText);
$userRow = $query->fetch_array();

$uCod = $_POST['codice_dettagli'];

$uCod = $dbCon->real_escape_string($uCod);

$check_cod = $dbCon->query("SELECT codice FROM eventi WHERE codice = '$uCod'");
$count = $check_cod->num_rows;

if($count == 0 ){
    $msg ="Evento non presente nel DB";
    header("Location: account_marco.php?errorMessage=" . $msg); }
?>

首选输出

<link rel="stylesheet" href="../css/style.css" type="text/css" media="screen">

</head>

我已经完成了以下操作，但这将通过目录结构而不是最低级别的目录逐个返回每个文件夹。

    <div class = "titolo_evento_selezionato">

        <?php

            $queryAlpha =  "
            SELECT NomeEvento, date_format(DataOra, '%d.%m.%y (%H:%i)') 
            FROM eventi
            WHERE BINARY codice = '" .$_POST['codice_dettagli'] . "' ";

            $queryEvento = $dbCon->query($queryAlpha);
            $EventoSelezionato = $queryEvento->fetch_array();


            echo($EventoSelezionato[0]);
            echo
            '<h7> 
                    <br>' . $EventoSelezionato[1] .'
                </h7>';

        ?>

    </div>      





    <form class = "seleziona_posto" method = "post" 
                action = "./acquista_evento_action.php? var = <?= $EventoSelezionato[0]; ?>" >


            <p> Seleziona sulla mappa il settore scelto e premi "Acquista" </p>

            <input class = "input_settore_css" type = "text" placeholder = "Settore posto" name = "input_settore" required >

            <input class = "bottone_settore_css" type = "submit" value = "ACQUISTA" name = "btn_settore">


    </form>



  </body>

感谢您的帮助

Answer 1

您可以这样做：

function GetLowestLevelRecursive([System.Collections.IList] $directories)
{
    $lowestleveldirs = @()
    foreach ($dir in $directories)
    {
        $childDirs = $dir.GetDirectories();
        if ($childDirs.Length -gt 0)
        {
            $lowestleveldirs += GetLowestLevelRecursive $childDirs
        }
        else
        {
            $lowestleveldirs += $dir
        }
    }
    return $lowestleveldirs
}

#input directories
$allDirectories = @()

# search for lowest level directories
$lowestlvldirs = GetLowestLevelRecursive $allDirectories

foreach ($dir in $lowestlvldirs)
{
    Write-Host $dir.FullName
}

预期输出：

C:\Users\Test\Desktop\xml\xml\User1\User1\user1\Windows\abc
C:\Users\Test\Desktop\xml\xml\User2\User2\user2\Windows1\abc

返回多个目录的最低级别目录

1 个答案: