一段时间以来,我一直对此代码有疑问。函数的递归调用的位置似乎不正确。
我尝试运行代码,是的,它确实遇到了无限循环。
// I DEFINE HEAP STRUCTURE AS :
struct heap_array
{
int *array; // heap implementation using arrays(note : heap is atype of a tree).
int capacity; // how much the heap can hold.
int size; //how much size is currently occupied.
void MaxHeapify(struct heap_array *h,int loc) // note : loc is the location of element to be PERCOLATED DOWN.
{
int left,right,max_loc=loc;
left=left_loc_child(h,loc);
right=right_loc_child(h,loc);
if(left !=-1 && h->array[left]>h->array[loc])
{
max_loc=left;
}
if(right!=-1 && h->array[right]>h->array[max_loc])
{
max_loc=right;
}
if(max_loc!=loc) //i.e. if changes were made:
{
//swap the element at max_loc and loc
int temp=h->array[max_loc];
h->array[max_loc]=h->array[loc];
h->array[loc]=temp;
}
MaxHeapify(h,max_loc); // <-- i feel that this recursive call is misplaced. I have seen the exact same code in almost all the online videos and some books i referred to. ALSO I THINK THAT THE CALL SHOULD BE MADE WITHIN THE SCOPE OF condition if(max_loc!=loc).
//if no changes made, end the func right there.
}
答案 0 :(得分:0)
在当前的实现中,您似乎没有停止递归的基本条件。
请记住,you need a base case in a recursive function(在这种情况下,是您的MaxHeapify
函数),看起来好像没有一个。
Here is an example of MaxHeap可能很有用
// A recursive function to max heapify the given
// subtree. This function assumes that the left and
// right subtrees are already heapified, we only need
// to fix the root.
private void maxHeapify(int pos)
{
if (isLeaf(pos))
return;
if (Heap[pos] < Heap[leftChild(pos)] ||
Heap[pos] < Heap[rightChild(pos)]) {
if (Heap[leftChild(pos)] > Heap[rightChild(pos)]) {
swap(pos, leftChild(pos));
maxHeapify(leftChild(pos));
}
else {
swap(pos, rightChild(pos));
maxHeapify(rightChild(pos));
}
}
}
在这里,您可以看到以下情况的基本情况:
if (isLeaf(pos))
return;
您需要在递归函数中添加一个基本案例。