Question

我有一张桌子Employee，

_________________________________
Id | name    |      salary                    
______________________________
1  | John    |   [1300 - 2000] 
_______________________________
2  | Aby     |   [600 - 1000] 
________________________________
3  | Mike    |   [1000 - 1500]

薪水栏为Nvarchar

我想要SQL中的Query / Function / SP，如果我搜索1400，则输出应如下所示

Id | name    |      salary                    
________________________________
1  | John    |   [1300 - 2000] 
_______________________________
3  | Mike    |   [1000 - 1500]

谢谢。

Answer 1

您不应将范围存储在一列中。但是，如果您无法更改它，那将是一种幻想：

SELECT  [Id] , name, 
      ,[salary] 
  FROM [Test Database].[dbo].[test] where 
1700 >= RTRIM(LTRIM(SUBSTRING(salary,0, CHARINDEX('-',salary)))) 
and 1700 <=  RTRIM(LTRIM(SUBSTRING(salary, CHARINDEX('-', salary) + 1, LEN(salary))))

Answer 2

您需要提取数字值，然后转换为数字类型：

declare @mySalary money;
set  @mySalary = 1400;

with Employee(ID, Name, Salary ) as
(
 select 1,'John','[1300 - 2000]' union all
 select 2,'Aby','[600 - 1000]'   union all
 select 3,'Mike','[1000 - 1500]'
), e2 as
(
select SUBSTRING(Salary,PATINDEX('%[0-9]%', Salary),CHARINDEX('-',Salary)-2) as Salary1,
       SUBSTRING(Salary,CHARINDEX('-',Salary)+1,CHARINDEX(']',Salary)-CHARINDEX('-',Salary)-1) as Salary2,
       e.*
  from Employee e
)
select ID, Name, Salary
  from e2
 where @mySalary between cast(Salary1 as money) and cast(Salary2 as money);

ID  Name    Salary
1   John    [1300 - 2000]
3   Mike    [1000 - 1500]

Demo

Answer 3

尝试此查询：

declare @tbl table (id int, name varchar(15), salary varchar(20));
declare @mySalary int = 1400;

insert into @tbl 
 select 1,'John','[1300 - 2000]' union all
 select 2,'Aby','[600 - 1000]'   union all
 select 3,'Mike','[1000 - 1500]'

select id, name, salary from (
    select id, name, salary,
           convert(int, substring(salary, openBrcktIdx + 1, hyphenIdx - openBrcktIdx - 2)) lowerBound,
           convert(int, substring(salary, hyphenIdx + 2, closeBrcktIdx - hyphenIdx - 2)) upperBound
    from (
        select *,
               charindex('-', salary) hyphenIdx,
               charindex('[', salary) openBrcktIdx,
               charindex(']', salary) closeBrcktIdx
        from @tbl
    ) t
) t where @mySalary between lowerBound and upperBound

Answer 4

声明@ var1 int = 1400

选择*从（选择*，replace（SUBSTRING（salary，0，CHARINDEX（'-'，salary，0）），'['，''）作为Splitted1， replace（SUBSTRING（salary，CHARINDEX（'-'，salary，0）+ 1，len（salary）-1），']'，''）as Splitted2 来自员工）作为t1 其中@ var1> = Splitted1和@ var1 <= Splitted2

https://rextester.com/l/sql_server_online_compiler

在字符串范围之间选择数据

4 个答案: