合并熊猫中的两个字符串列表

Question

我有一个带有两个x和y序列的数据框。我想将它们合并以创建一个新的series：标签，但是我无法实现预期的输出。我尝试过：

df['tag'] = df['x'] + df['y']

我到处都是，却找不到解决问题的方法。

当前输出：

x                               y           tag
['fast food', 'american']   ['chicken'] ['fast food', 'american']['chicken']

预期输出：

x                               y           tag
['fast food', 'american']   ['chicken'] ['fast food', 'american', 'chicken']

df.to_dict（）

{'x': "['fast food', 'american']",
 'y': "['chicken']"}

Answer 1

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sum

---

更多信息

import ast
df.x = df.x.apply(ast.literal_eval)
df.y = df.y.apply(ast.literal_eval)

df['tag'] = df['x'] + df['y']

Answer 2

另一种方法是使用re.findall：

import re

df.applymap(lambda x:re.findall("'(.+?)'", x)).sum(1)

将返回list中的str：

                           x            y                             tag
0  ['fast food', 'american']  ['chicken']  [fast food, american, chicken]

Answer 3

您可以解压缩列表，然后使用Apply创建新列。

Answer 4

已更新

尝试一下：

df=pd.DataFrame()
df['X']=[["chicken"]]
df['Y']=[["fast food","American"]]
df['tag']=df['X']+df['Y']