我正在使用PHP来从电子邮件正文中获取cid图像。我想删除cid:ii_jv1bt7pm0
,cid:HeaderImage
或网址末尾显示的所有内容。
当我尝试这样做时:
$cid = 'cid:'.substr($cid, 1, strlen($cid)-2);
它将在网址末尾显示cid,例如:
所以我想实现使其显示为这样:
http://example.com/#inbox/u/?id=123456&attid=0.1&msgid=1630808059112201633&view=attachment&display=view
这是$cid
的输出:
cid:ii_jv1bt7pm0
cid:HeaderImage
我想删除字符串以将其替换为空字符串,以使这些字符串不会显示在网址末尾。
这是完整的代码:
<?php
require_once "Mail.php";
require_once('Mail/IMAPv2.php');
$username = 'myusername';
$password = 'mypassword';
$mailserver = '{imap.example.com:993/imap/ssl/novalidate-cert}'.$_POST['mailserver'];
$mailbox = imap_open($mailserver, $username, $password) or die("Can't connect: " . imap_last_error());
email_number = 'somerandomnumbers';
$attachment = getAttachment($mailbox, $email_number);
function getAttachment(&$mail, $email_number) {
$attachments = $mail->attachments;
$msgNo = trim($mail->headerInfo->Msgno);
$key = "somekeys";
$email_id = bin2hex(openssl_encrypt($email_number, 'AES-128-CBC', $key));
$attach_id = 0;
$inline_id = 0.1;
$html = '';
foreach ($attachments as $attachment) {
$partNo = $attachment['part'];
$filename = $attachment['filename'];
$filename = htmlentities($filename);
$cid = $attachment['id'];
if (isset($cid)) {
if (strpos($mail->htmlText, 'viewHeaderImage')) {
$mail->htmlText = str_replace('viewHeaderImage', 'view', $mail->htmlText);
}
else {
$cid = 'cid:'.substr($cid, 1, strlen($cid)-2);
}
if($filename == 'noname.gif') {
$tempfile = '/u/?id='.$email_id.'&attid='.$inline_id.'&msgid=1630808059112201633&view=attachment&display=view';
}
else {
$tempfile = '/u/?id='.$email_id.'&attid='.$inline_id.'&msgid=1630808059112201633&view=attachment&display=view';
}
$mail->htmlText = EmailEmbeddedLinkReplace($mail->htmlText, $cid, $tempfile);
}
}
}
function EmailEmbeddedLinkReplace($html, $cid, $link)
{
// In $html locate src="cid:$cid" and replace with $link.
$cid = 'cid:'.substr($cid, 1, strlen($cid)-2);
$newHtml = str_replace($cid, $link, $html);
return $newHtml;
}
我尝试使用$cid = '';
,但不会有任何区别,因为cid仍会显示在网址末尾。
您能给我一个例子来说明如何删除cid:ii_jv1bt7pm0
,cid:HeaderImage
或如何删除它,以使它们不会显示在网址末尾吗? / p>
答案 0 :(得分:1)
抱歉,我不完全了解您问题的性质。但是,
$cid = "http://example.com/#inbox/u/?id=123456&attid=0.1&msgid=1630808059112201633&view=attachment&display=viewii_jv1bt7pm0";
$cid = substr($cid,0,strrpos($cid,"display=view")+12);
echo $cid;
在这段代码中,我使用strrpos
查找了display=view
的最后一个$cid
,然后加上了display=view
的长度,即12。从0-index
到end-index
的{{1}}的URL。
以上代码的输出为:
希望这会有所帮助
答案 1 :(得分:1)
根据您在EmailEmbeddedLinkReplace()
中的评论,看来这是您需要的:
function EmailEmbeddedLinkReplace($html, $cid, $link)
{
// In $html locate src="cid:$cid" and replace with $link.
return str_replace('src="cid:'.$cid.'"', $link, $html);
}
答案 2 :(得分:0)
使用rtrim
从字符串中删除最后一个str。
echo rtrim("http://example.com/#inbox/u/?id=123456&attid=0.1&msgid=1630808059112201633&view=attachment&display=viewii_jv1bt7pm0","ii_jv1bt7pm0");