Question

我有一个程序，可以对excel文件进行一些操作。我正在尝试为此创建一个GUI。我需要用户浏览他的计算机并选择他要通过该过程的excel文件。但我无法将PyQT文件打开器的地址提供给熊猫。熊猫和numpy以及其他所有内容均已导入。我只是无法链接这两个。


def selectFile(self):
        options = QFileDialog.Options()
        options |= QFileDialog.DontUseNativeDialog
        fileName, _ = QFileDialog.getOpenFileName(self,"Open File", "","All Files (*);;Excel Files (*.xlsx)", options=options)
        # print(fileName)
        if fileName:
            # df=pd.read_excel(fileName,Header=None)
            self.variableOne = fileName
            return self.variableOne
            print(self.variableOne)

address=''
    df=pd.read_excel(selectFile(address), header=None)
    data=np.asarray(df)

我收到错误消息：

fileName, _ = QFileDialog.getOpenFileName(self,"Open File", "","All Files (*);;Excel Files (*.xlsx)", options=options)
TypeError: getOpenFileName(parent: QWidget = None, caption: str = '', directory: str = '', filter: str = '', initialFilter: str = '', options: Union[QFileDialog.Options, QFileDialog.Option] = 0): argument 1 has unexpected type 'str'

如何从Qt5输入对话框中获取地址？

0 个答案: