Question

我又被卡住了！我的故事是：

我需要找到一个目录中不同文件夹中存在的名为“ tv.sas7bdat”的文件，并将找到的所有文件的内容保存到桌面上的单个excel文件中。使用我的实际代码，我可以获取该文件的所有路径，并将其内容传输到数据框。但是，我无法将所有数据框附加到一个Excel文件中。

在我的Excel中，我仅找到最后一个数据帧！！

这是我的代码

import pandas as pd
from sas7bdat import SAS7BDAT
import os

path = "\\"
newpath = "\\"

files = []
# r=root, d=directories, f = files
for r, d, f in os.walk(path):
    for file in f:
        if 'tv.sas7bdat' in file:
            files.append(os.path.join(r,  file))

lenf = range(len(files))
for f in files:
    print(f)

for df in lenf:

    with SAS7BDAT(f) as file:
        df = file.to_data_frame()
        print(df)

    group =pd.concat([df], axis=0, sort=True, ignore_index = True)
    df.to_excel(newpath + 'dataframes_tv.xlsx',index=False)

Answer 1

您可能想使用shutil模块，它允许您使用copytree函数复制目录及其中的文件。示例：

import shutil
shutil.copytree('/path/to/source', 'path/to/destination')

Answer 2

如果不想更改代码，则可以enumerate通过从列表中获取第一个文件，将初始数据帧分配为一侧的占位符，enumerate来拆分该过程。列表中的其余文件，以将所有其他数据帧附加到初始文件中

编辑 files和# save the first dataframe from 1st list element df = SAS7BDAT(files[0]).to_data_frame() # enumerate the list to access greater elements for k, f in enumerate(files): # from 2nd element onward if k > 0: with SAS7BDAT(f[k]) as file: # append all elements to the 1st df = df.append(file.to_data_frame()) group = pd.concat([df], axis=0, sort=True, ignore_index=True) df.to_excel('dataframes_tv.xlsx', index=False)列表中的代码片段

    private MemoryStream GetFileIcon(string name, IconReader.IconSize size)
    {
        Icon icon = IconReader.GetFileIcon(name, size, false);
        using (icon)
        {
            Bitmap bmp = icon.ToBitmap();
            MemoryStream ms = new MemoryStream();
            bmp.Save(ms, System.Drawing.Imaging.ImageFormat.Png);
            ms.Seek(0, SeekOrigin.Begin);
            return ms;
        }
    }

    public bool ProcessRequest(IRequest request, ICallback callback)
    {
        Uri uri = new Uri(request.Url);
        string fileName = uri.AbsolutePath;

        if (uri.Host == "storage")
        {
            fileName = appPath + uri.Host + fileName;
            if (File.Exists(fileName))
            {
                Task.Factory.StartNew(() =>
                {
                    using (callback)
                    {
                        //var bytes = Encoding.UTF8.GetBytes(resource);
                        //stream = new MemoryStream(bytes);
                        FileStream fStream = new FileStream(fileName, FileMode.Open, FileAccess.Read);
                        mimeType = ResourceHandler.GetMimeType(Path.GetExtension(fileName));
                        stream = fStream;
                        callback.Continue();
                    }
                });

                return true;
            }
        }

        if (uri.Host == "fileicon")
        {
            Task.Factory.StartNew(() =>
            {
                using (callback)
                {
                    stream = GetFileIcon(fileName, IconReader.IconSize.Large);
                    mimeType = ResourceHandler.GetMimeType(".png");
                    callback.Continue();
                }
            });
            return true;
        }

        return false;
    }
    public bool ReadResponse(Stream dataOut, out int bytesRead, ICallback callback)
    {
        //Dispose the callback as it's an unmanaged resource, we don't need it in this case
        callback.Dispose();

        if (stream == null)
        {
            bytesRead = 0;
            return false;
        }

        //Data out represents an underlying buffer (typically 32kb in size).
        byte[] buffer = new byte[dataOut.Length];
        bytesRead = stream.Read(buffer, 0, buffer.Length);

        dataOut.Write(buffer, 0, buffer.Length);

        return bytesRead > 0;
    }
}}

将粘贴文件从不同目录复制到一个文件夹

2 个答案: