Question

我想构建一个自动登录机器人（程序或某物）。我想知道它是否使用给定的密码登录。因此，我想验证错误消息，指出用户名或密码无效，并且该消息是否打开了程序，或者自动登录机器人显示了“未登录”警报，并且如果该消息没有打开机器人鞋，警报“已登录”，但是当我给漫游器输入错误的密码并且出现“无效密码”消息时，漫游器也会显示警报“已登录”！另一个问题：当我要构建* .py文件时，代码“ print（已登录）”有效，但是“已登录”警报关闭得非常快，无法读取警报。

这是我的第一个也是主要问题的代码：

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

driver = webdriver.Firefox()
driver.get("https://www.instagram.com/accounts/login/")

username =WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//input[@name='username']")))
password =WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//input[@name='password']")))
username.clear()
username.send_keys("My Username")
password.clear()
password.send_keys("My Password")
try:
    element = WebDriverWait(driver, 10).until(
        EC.element_to_be_clickable((By.XPATH, "//button[@type='submit']"))
    )
finally:
    element.click()

if len(driver.find_elements_by_xpath("//form[@id='slfErrorAlert']"))>0:
    # Element is present
    print("Not!")
else:
    # Element is not present
    print ("Logged IN!")

这是我每次得到的：

>>> from selenium import webdriver
>>> from selenium.webdriver.common.keys import Keys
>>> from selenium.webdriver.common.by import By
>>> from selenium.webdriver.support.ui import WebDriverWait
>>> from selenium.webdriver.support import expected_conditions as EC
>>>
>>> driver = webdriver.Firefox()
>>> driver.get("https://www.instagram.com/accounts/login/")
>>>
>>> username =WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//input[@name='username']")))
>>> password =WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//input[@name='password']")))
>>> username.clear()
>>> username.send_keys("My Username")
>>> password.clear()
>>> password.send_keys("My Password")
>>> try:
...     element = WebDriverWait(driver, 10).until(
...         EC.element_to_be_clickable((By.XPATH, "//button[@type='submit']"))
...     )
... finally:
...     element.click()
...
>>> if len(driver.find_elements_by_xpath("//form[@id='slfErrorAlert']"))>0:
...     # Element is present
...     print("Not!")
... else:
...     # Element is not present
...     print ("Logged IN!")
...
Logged IN!

Answer 1

尝试以下代码。如果您输入了错误的用户名或密码，则应返回Not！并且如果您提供有效的用户名和密码，它应该在隐式等待的帮助下返回登录状态。

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

driver = webdriver.Firefox()
driver.get("https://www.instagram.com/accounts/login/")

username =WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//input[@name='username']")))
password =WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//input[@name='password']")))
username.clear()
username.send_keys("My Username")
password.clear()
password.send_keys("My Password")
try:
    element = WebDriverWait(driver, 10).until(
        EC.element_to_be_clickable((By.XPATH, "//button[@type='submit']"))
    )
finally:
    element.click()

driver.implicitly_wait(2)
if len(driver.find_elements_by_xpath("//p[@id='slfErrorAlert']"))>0:
    # Element is present
    print("Not!")
else:
    # Element is not present
    print ("Logged IN!")

无法验证元素

1 个答案: