Question

我正在尝试在Spring Boot application中创建一个简单的STS 3，用户可以在其中注册并创建他们的帐户。我正在将PostgreSQL数据库和JPA与休眠一起使用。以下是代码。

实体类：

package tv.app.user;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;

@Entity
public class UserAccount {
    @Id
    @GeneratedValue
    private Long uid;

    private String username;
    private String email;
    private String password;

    public long getUid() {
        return uid;
    }

    public void setUid(long uid) {
        this.uid = uid;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }
}

控制器：

package tv.app.user;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;

@Controller
public class UserAccountController {

    @Autowired
    UserAccountService userAccountService;

    @RequestMapping(value="/register", method=RequestMethod.POST)
    public void registerAccount(@RequestBody UserAccount user) {
        System.out.println("------2------");
        System.out.println(user.getfName());
        userAccountService.register(user);
    }
}

存储库：

package tv.app.user;

import org.springframework.data.repository.CrudRepository;

public interface UserAccountRepository extends CrudRepository<UserAccount, Long> {

}

商务服务类：

package tv.app.user;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;

@Service
public class UserAccountService {

    @Autowired
    private UserAccountRepository userRepository;

    public void register(UserAccount user) {
        userRepository.save(user);
    }
}

Jsp表单：

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
    <form action="/register" method="post">
        <input type="text" name="username" placeholder="Username" required /><br>
        <input type="text" name="email" placeholder="Email ID" required /><br>
        <input type="password" name="password" placeholder="Password" required /><br>
        <input type="submit" value="Signup" />
    </form>
</body>
</html>

application.properties 文件：

spring.jpa.properties.hibernate.jdbc.lob.non_contextual_creation=true

spring.jpa.hibernate.ddl-auto=create

spring.datasource.initialization-mode=always
spring.datasource.platform=postgres
spring.datasource.url=jdbc:postgresql://localhost:5432/myApp
spring.datasource.username=postgres
spring.datasource.password=postgres

似乎单击提交后，控件永远不会进入控制器，因为--- 2 ---永远不会输出到控制台，即使表单中的操作与请求映射相同。

显示的错误是：

发生意外错误（类型=不支持的介质类型，状态= 415）。内容类型'application / x-www-form-urlencoded; charset = UTF-8'不支持

Answer 1

确保您正在调用在控制器中声明的确切端点（localhost：port / register）。如果您未正确调用，则可能会输出HTTP 404错误...检查该错误。

如果没有任何HTTP错误，我将注释更改为这种格式（并将调用相应地更改为/ register / user）（如Spring指南here所示）：

@RestController
@RequestMapping("/register")
public class UserAccountController {

@Autowired
UserAccountService userAccountService;

@PostMapping("/user")
public void registerAccount(@RequestBody UserAccount user) {
    System.out.println("------2------");
    System.out.println(user.getfName());
    userAccountService.register(user);
}
}

为什么控制器代码无法在Spring Boot应用程序中执行

1 个答案: