Question

我的elif行不断出现语法错误（箭头指向“ elif”的结尾。

我正在尝试编写一个程序，该程序允许用户输入3D形状，然后输入一些数据来计算其体积。但是，我不断收到语法错误，箭头指向我的“ elif”结尾。

我正在使用https://www.onlinegdb.com/online_python_interpreter作为控制台。

# Allows the use of Pi
import math

# Where the user selects the 3D shape
shape = str(input("Enter a Shape you would like to find the volume of! : "))

# Where it takes the user to a shape calculator based on what shape the user inputted
if shape == ("Sphere"):
    def vsphere(r):
        volume = 4.0/3.0*math.pi*r**3
        return volume
# Where the user enters the data of the shape
    radius = float(input("Enter The Volume of Your Sphere! : "))

    print("The Volume of a Sphere with a Radius of ",str(radius)," is ",str(vsphere(radius)))

elif shape == ("Cylinder"):
    def vcylinder(n):
        volume = math.pi * r**2 * h
        return n

r = int(input("Enter the Radius! : "))
h = int(input("Enter the Height! : "))

print("The Volume of a Cylinder with a Radius of ",str(r)," and a Height of ",str(h)," is ",str(vcylinder(math.pi * r**2 * h)))

elif shape == ("Cone"):
    def vcone(n):
        volume = math.pi * r**2 * h * 1/3
        return n

r = int(input("Enter the Radius! : "))
h = int(input("Enter the Height! : "))

print("The Volume of a Cylinder with a Radius of ",str(r)," and a Height of ",str(h)," is ",str(vcone(math.pi * r**2 * h * 1/3)))

elif shape == ("Cube"):
    def vcube(a):
        volume = a**3
        return volume

a = int(input("Enter the Area! : "))

print("The Volume of a Cube with an Area of ",str(a)," is ",str(vcube(a)))

else:
    print("Sorry, that Shape isn't on our List")

    print("Sorry, that Shape isn't on our List")

它应该允许用户输入一个形状（如立方体），将其带到形状计算器（输入立方体的面积），然后根据输入的数据计算体积。

相反，当我运行程序时，它会显示以下错误消息：

文件“ main.py”，第27行
elif shape ==（“圆锥”）：
^
SyntaxError：语法无效

Answer 1

您遇到缩进错误问题。

您必须缩进

    r = int(input("Enter the Radius! : "))
    h = int(input("Enter the Height! : "))

如果我们不缩进，则视为退出if块。因此，当我们在elif之外遇到if时，会得到语法错误。

# Allows the use of Pi
import math

# Where the user selects the 3D shape
shape = str(input("Enter a Shape you would like to find the volume of! : "))

# Where it takes the user to a shape calculator based on what shape the user inputted
if shape == ("Sphere"):
    def vsphere(r):
        volume = 4.0/3.0*math.pi*r**3
        return volume
# Where the user enters the data of the shape
    radius = float(input("Enter The Volume of Your Sphere! : "))

    print("The Volume of a Sphere with a Radius of ",str(radius)," is ",str(vsphere(radius)))

elif shape == ("Cylinder"):
    def vcylinder(n):
        volume = math.pi * r**2 * h
        return n

    r = int(input("Enter the Radius! : "))
    h = int(input("Enter the Height! : "))

    print("The Volume of a Cylinder with a Radius of ",str(r)," and a Height of ",str(h)," is ",str(vcylinder(math.pi * r**2 * h)))

elif shape == ("Cone"):
    def vcone(n):
        volume = math.pi * r**2 * h * 1/3
        return n

    r = int(input("Enter the Radius! : "))
    h = int(input("Enter the Height! : "))

    print("The Volume of a Cylinder with a Radius of ",str(r)," and a Height of ",str(h)," is ",str(vcone(math.pi * r**2 * h * 1/3)))

elif shape == ("Cube"):
    def vcube(a):
        volume = a**3
        return volume

    a = int(input("Enter the Area! : "))

    print("The Volume of a Cube with an Area of ",str(a)," is ",str(vcube(a)))

else:
    print("Sorry, that Shape isn't on our List")

    print("Sorry, that Shape isn't on our List")

Answer 2

您正在缩进。

您的elif的缩进级别必须相同

。 Cylinder的计算必须在elif shape == ("Cylinder"):中。

elif shape == ("Cylinder"):
    def vcylinder(n):
        volume = math.pi * r**2 * h
        return n
# vvvvvvvvvvvvvvvvvv NEED INDENTATION vvvvvvvvvvvvvvvvvv 
r = int(input("Enter the Radius! : "))
h = int(input("Enter the Height! : "))

print("The Volume of a Cylinder with a Radius of ",str(r)," and a Height of ",str(h)," is ",str(vcylinder(math.pi * r**2 * h)))
# ^^^^^^^^^^^^^^^^^^ NEED INDENTATION ^^^^^^^^^^^^^^^^^^
elif shape == ("Cone"):
    def vcone(n):
        volume = math.pi * r**2 * h * 1/3
        return n

ps：比较2个字符串时无需使用括号

如何修复“语法错误，语法无效”（无上下文或原因）Elif函数Python

2 个答案: