Question

我在Powershell脚本中有多行数据，如下所示：

SSAS=PerformanceAnalysisService, Provider=SQLNCLI11.1;Data Source=LAP123;Integrated Security=SSPI;Initial Catalog=PerformanceDataMart:
SSAS=EnvironmentalAnalysisService, Provider=SQLNCLI11.1;Data Source=LAP123;Integrated Security=SSPI;Initial Catalog=EnvironmentalDataMart:

我当前正在使用：

ConvertFrom-String -Delimiter ";" -PropertyNames Server, Provider, Source, Security, Catalog.

哪个给我：

Server                                                  Provider            Source                   Security                              
------                                                  --------            ------                   --------                              
SSAS=EnvironmentalAnalysisService, Provider=SQLNCLI11.1 Data Source=LAP123  Integrated Security=SSPI Initial Catalog=EnvironmentalDataMart:
SSAS=PerformanceAnalysisService, Provider=SQLNCLI11.1   Data Source=DEV-EDW Integrated Security=SSPI Initial Catalog=PerformanceDataMart:

我想创建一个表，以键作为列标题，或者甚至能够从表数据中删除键。

+------------------------------+-------------+-------------+-----------------+-----------------------+
|            SSAS              |  Provider   | Data Source |    Security     |    Catalog            |
+------------------------------+-------------+-------------+-----------------+-----------------------+
| EnvironmentalAnalysisService | SQLNCLI11.1 | LAP123      | Integrated SSPI | EnvironmentalDataMart |
| PerformanceAnalysisService   | SQLNCLI11.1 | LAP123      | Integrated SSPI | PerformanceDataMart   |
+------------------------------+-------------+-------------+-----------------+-----------------------+

但是有没有办法识别键/列名并动态地删除它们呢？

最终结果将由SQL使用。因此，要么将数据作为单独的列返回，要么将逗号分隔都很好。

Answer 1

ConverTo-Csv应该能够做到这一点，只需将ConvertFrom-String的输出传递给它即可。

> $in = "SSAS=PerformanceAnalysisService, Provider=SQLNCLI11.1;Data Source=LAP123;Integrated Security=SSPI;Initial Catalog=PerformanceDataMart:","SSAS=EnvironmentalAnalysisService, Provider=SQLNCLI11.1;Data Source=LAP123;Integrated Security=SSPI;Initial Catalog=EnvironmentalDataMart:"
> $in | ConvertFrom-String -Delimiter ";" -PropertyNames Server, Provider, Source, Security, Catalog | ConvertTo-Csv -NoTypeInformation -Delimiter ';'
"Server";"Provider";"Source";"Security"
"SSAS=PerformanceAnalysisService, Provider=SQLNCLI11.1";"Data Source=LAP123";"Integrated Security=SSPI";"Initial Catalog=PerformanceDataMart:"
"SSAS=EnvironmentalAnalysisService, Provider=SQLNCLI11.1";"Data Source=LAP123";"Integrated Security=SSPI";"Initial Catalog=EnvironmentalDataMart:"

如果要将内容存储到CSV文件中，也可以将ConverTo-Csv替换为Export-Csv，或者可以将ConvertTo-Csv的输出通过管道传输到Out-File

希望有帮助

Powershell从键值对创建表，并以键作为列标题

1 个答案: