Question

如何从Selenium Webdriver中的以下URL获取syskey_request_token： https://gimain03.uat.income.com.sg/insurance/mainMenu.do?syskey_request_to ken = 2b7c09eda6d7acf3b95b6745152cf521

Answer 1

您可以使用正则表达式来处理它，例如：

import re 

currentPageUrl = driver.current_url
syskey_request_token = re.findall('syskey_request_token=.*', currentPageUrl)[0]

Answer 2

再次引起我一些误解，这是Java解决方案：

import org.openqa.selenium.WebDriver;
import org.openqa.selenium.chrome.ChromeDriver;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class main {
    public static void main(String[] args) {
        openChrome();
    }
    /**
     * open chrome driver
     */
    public static void openChrome() {
        // path of driver
        System.setProperty("webdriver.chrome.driver", "driver\\chromedriver.exe");
        WebDriver driver = new ChromeDriver();
        // Typing your URL below
        driver.get("xxx://xxx.xxx.xxx");
        String currentURL = driver.getCurrentUrl();
        // Using regex to find key 'syskey_request_token='
        Pattern pattern = Pattern.compile("syskey_request_token=(.*)");
        Matcher matcher = pattern.matcher(currentURL);
        matcher.find();
        System.out.print(currentURL+"\n");
        System.out.print(matcher.group(1)+"\n");
    }
}

嗨，我如何从硒中的URL获取响应令牌

2 个答案: