Question

我是Java语言的新手，我正尝试从中创建联系人并对其进行验证，但是，正如您在下面看到的那样，我不知道它是否是...

console.log('Email is valid!');

...或其他任何内容，但之后警报的其他部分将无法工作！谁知道怎么修它？感谢您的帮助！

if (name === '') {
  alert('Pls enter your name!')
} else if (name.length < 2) {
  alert('Pls enter a valid name! Longer than 2 letters');
} else if (name.length > 20) {
  alert('Pls enter a valid name! Less than 20 letters');
} else if (email === '') {
  alert('Empty Email. Pls enter your email!')
} else if (!validateEmail(email)) {
  alert('Email is not valid!');
} else if (validateEmail(email)) {
  console.log('Email is valid!');
} else if (message.length < 1) {
  alert('Pls enter a Message!')
} else if (message.length < 5) {
  alert('Pls enter a message longer than 5 letters!')

Answer 1

请阅读if-else-if的工作方式，它只会执行所有条件的 one 并立即退出。如果要执行所有警报，只需执行一堆ifs：

if (name === '') {
  alert('Pls enter your name!')
} 

if (name.length < 2) {
  alert('Pls enter a valid name! Longer than 2 letters');
} 

if (name.length > 20) {
  alert('Pls enter a valid name! Less than 20 letters');
} 

if (email === '') {
  alert('Empty Email. Pls enter your email!')
} 

if (!validateEmail(email)) {
  alert('Email is not valid!');
} 

if (validateEmail(email)) {
  console.log('Email is valid!');
} 

if (message.length < 1) {
  alert('Pls enter a Message!')
} 

if (message.length < 5) {
  alert('Pls enter a message longer than 5 letters!')
}

console.log在它之后停止警报

1 个答案: