Question

编写一个程序，接受用户输入并通过一些功能运行它。我无法在其中一项功能中更改数据以更改主数据。

#include <stdio.h>

int convertLoot (int gold , int silver , int bronze, int total);
int convertBronze (int total, int gold, int silver, int bronze);
int Spend (int total);


int main()
{
    int gold, silver, bronze, total, *Ntotal ;
    Ntotal= &total;
    printf("Please enter loot amounts.\n");
    printf ("Gold>");
    scanf("%d", &gold);
    printf ("Siver>");
    scanf("%d", &silver);
    printf("bronze>");
    scanf("%d", &bronze);
    convertLoot ( gold, silver, bronze, total );
    printf("total is %d bronze \n", *Ntotal);
    convertBronze(total, gold, silver, bronze); 
    printf("Total loot is %d gold %d silver %d bronze \n", gold, silver, bronze);

    Spend ( total);
    convertBronze(total, gold, silver, bronze); 
    printf("total is %d bronze \n", *Ntotal);   
    printf("Total loot is now %d gold %d silver %d bronze \n", gold, silver, bronze);
    return (0);
}

// Converts loot in bronze. 
int convertLoot (int gold, int silver, int bronze, int total)
{
int conGold= gold*100;
int conSilver=silver*10;
int conTotal=conGold+conSilver+bronze;
     total=conTotal;


    return 0;   
}

//Convert Bronze Function.
//Take Total Bronze and reconverts it to Gold Silver and Bronze.
int convertBronze (int total, int gold, int silver, int bronze)
{

 gold=total/100;
 total=total%100;
 silver=total/10;
 bronze=total%10;

return 0;
}


// spend function
int Spend (int total)
{
int SubGold;
int SubSilver;
int SubBronze;
int Choice;
int *Ntotal;
Ntotal= &total;
printf("What do you wish to spend? \n");
printf("1 for Gold , 2 for Silver, 3 for Bronze \n");
scanf("%d", &Choice);
if (Choice== 1){
printf("How much Gold? \n");
scanf ("%d" , &SubGold);
*Ntotal=total-(SubGold*100);
return 0;
}
else if (Choice== 2){
printf("How munch Silver? \n");
scanf("%d" , &SubSilver);
*Ntotal=*Ntotal-(SubSilver*10);

}
else if (Choice== 3){
printf("How much Bronze? \n");
scanf("%d" , &SubBronze);
*Ntotal=*Ntotal-(SubBronze);

return 0;
}
}

来自Spend函数的更改，对main中的“ total”变量没有影响。支出函数调用之后的第二个printf语句显示与调用之前相同的内容。

Answer 1

在C语言中，可以通过两种方式将值传递给函数：

按值传递
通过引用传递

请参阅此文章以获取更多信息：

https://www.geeksforgeeks.org/difference-between-call-by-value-and-call-by-reference/

为什么我的函数中的数据不传回Main？

1 个答案: