Question

我希望函数执行X（= 3）次直到成功。

我知道这个问题看起来与this question类似，但是所有答案都无济于事。

我只想将此消息发送为松弛状态，如果失败，请重试3次。

const options = {
    'text': 'Hello'
  }

let flag = 0
  function sendMessage () {
    const promise = new Promise((resolve, reject) => {
      axios.post(webhookURL, JSON.stringify(options))
        .then(response => {
          flag++
          return resolve('SUCCESS: Sent slack webhook', response.data)
        })
        .catch(error => {
          return reject(new Error('FAILED: Sent slack webhook', error))
        })
    })
    return promise
  }

  for (let maxRetry = 0; maxRetry < 3; maxRetry++) {
    const p = sendMessage()
    p
      .then((status) => {
        console.log(status)
      })
      .catch((err) => {
        console.log(err)
      })
    console.log('flag', flag)
    if (flag >= 1) {
      break
    }
  }

即使成功，它也会运行3次。承诺工作不正常输出

flag 0
flag 0
flag 0
SUCCESS: Sent slack webhook
SUCCESS: Sent slack webhook
SUCCESS: Sent slack webhook

我是nodejs的新手。如果你们中的任何人都可以在这里帮助我，将会非常有帮助。

Answer 1

有一个使用async/await功能的解决方案，这将使您可以等待对诺言的解析，然后再运行对异步函数的另一次调用

成功示例：

//const axios = require('axios');

function sendMessage() {
  return new Promise((resolve, reject) => {
    axios
      .get('https://jsonplaceholder.typicode.com/posts/1')
      .then(response => {
        resolve('SUCCESS: Sent slack webhook', response.data);
      })
      .catch(error => {
        reject(new Error('FAILED: Sent slack webhook', error));
      });
  });
}

(async function loop() {
  for (let i = 0; i < 3; i++) {
    console.log('loop count = ', i);
    try {
      const res = await sendMessage();
      console.log(res);
      break;
    } catch (error) {
      console.log(error);
    }
  }
})();

<script src="https://unpkg.com/axios/dist/axios.min.js"></script>

错误示例：

//const axios = require('axios');

function sendMessage() {
  return new Promise((resolve, reject) => {
    axios
      .get('https://falseurl')
      .then(response => {
        resolve('SUCCESS: Sent slack webhook', response.data);
      })
      .catch(err => {
        console.log('FAILED: Sent slack webhook')
        reject(new Error('FAILED: Sent slack webhook', err));
      });
  });
}

(async function loop() {
  for (let i = 0; i < 3; i++) {
    console.log('loop count = ', i);
    try {
      const res = await sendMessage();
      console.log(res);
      break;
    } catch (err) {
      console.log(err);
    }
  }
})();

<script src="https://unpkg.com/axios/dist/axios.min.js"></script>

如果X次失败，则nodejs sendMessage函数

1 个答案: