Question

我想在一栏中对excel文件实施操作该列具有字符串和整数数据，但该列是对象类型

我的数据在Excel中看起来像：（字符串和数字的组合）

Time Spent
3600
0
None
1800
0

我尝试了以下代码


if (df['Time Spent']=='None').all():
 df['Time Spent'] = 0
else:
 df['Time Spent'] = df['Time Spent'].astype('int')/3600

我得到的错误

Index([u'Issue Key', u'Issue Id', u'Summary', u'Assignee', u'Priority',
       u'Issue Type', u'Status', u'Tag', u'Original Estimate', u'Time Spent',
       u'Resolution Date', u'Created Date'],
      dtype='object')
Traceback (most recent call last):
  File "dashboard_migration_graph_Resolved.py", line 60, in <module>
    df['Time Spent'] = df['Time Spent'].astype('int')/3600
  File "/usr/lib64/python2.7/site-packages/pandas/util/_decorators.py", line 118, in wrapper
    return func(*args, **kwargs)


  File "pandas/_libs/lib.pyx", line 854, in pandas._libs.lib.astype_intsafe
  File "pandas/_libs/src/util.pxd", line 91, in util.set_value_at_unsafe
ValueError: invalid literal for long() with base 10: 'None'

Answer 1

将to_numeric与errors='coerce'一起使用将所有非数字转换为缺失值，因此在除法之前添加Series.fillna：

df['Time Spent'] = pd.to_numeric(df['Time Spent'], errors='coerce').fillna(0)/3600
print (df)
   Time Spent
0         1.0
1         0.0
2         0.0
3         0.5
4         0.0

如果需要None像丢失值一样返回，只需删除fillna-取而代之的是None得到丢失值NaN，因此可能需要多列：

df['Time Spent'] = pd.to_numeric(df['Time Spent'], errors='coerce')/3600
print (df)
   Time Spent
0         1.0
1         0.0
2         NaN
3         0.5
4         0.0

Answer 2

我无法发表评论（由于声誉低下），但您尝试了吗：

df['Time Spent'] = df['Time Spent'].replace('None', 0). astype(int)/3600

希望这对您有用。

从Dataframe对象-python过滤字符串和整数值

2 个答案: