Question

我正在用nodejs制作一个应用程序，我想对我的模型进行连接，但是我仍然遇到相同的错误：

TypeError：user.findAll不是函数

routes / user.js

const express = require('express');
const router = express.Router();
const db = require('../config/database');
const user = require('../models/users');

router.get('/', (req, res) => user.findAll()
.then(users =>  {
    console.log(users)
    res.sendStatus(200);
     })
.catch(err => console.log(err)));

module.exports = router;

models / user.js

'use strict';

const Sequelize = require('sequelize');
const db = require('../config/database')

module.exports = (sequelize, DataTypes) => {
  const users = sequelize.define('users', {
    id: DataTypes.INTEGER,
    name: DataTypes.STRING,
    age: DataTypes.INTEGER,
    email: DataTypes.STRING,
    country: DataTypes.STRING,
    state: DataTypes.STRING,
    city: DataTypes.STRING
  }, {});
  users.associate = function(models) {
    // associations can be defined here
  };
  return users;
};

Answer 1

您应该使用db.users.findAll()而不是user.findAll()。它会工作

Answer 2

我发现了错误，我无法正确导入/导出，我将我的models / user.js文件更改为：

'use strict';
const Sequelize = require('sequelize');
const db = require ('../config/database')
const DataTypes = require('sequelize/lib/data-types')

const User = db.define('users', {
  name: DataTypes.STRING,
  age: DataTypes.INTEGER,
  email: DataTypes.STRING,
  country: DataTypes.STRING,
  state: DataTypes.STRING,
  city: DataTypes.STRING

  }, {});
  User.associate = function(models) {
    // associations can be defined here
  };
module.exports = User

findAll（）不是函数续集

2 个答案: