Question

我正在执行命令，其中将特定角色添加到所有成员。问题在于，.forEach循环对于API来说太快了。

我知道我可能必须以某种方式使用setIntervall解决此问题。

module.exports.run = async (bot, message, args, level) => {
    if (!args || args.length < 1) return message.reply("Must provide a role to give. Derp.");


    let role = message.guild.roles.find(r => r.name == args[0])

    if (!role) return message.channel.send(`**${message.author.username}**, role not found`)

        let msg = await message.channel.send("Ur lazy")

        message.guild.members.filter(m => !m.user.bot).forEach(member => member.addRole(role))


        message.channel.send(`**${message.author.username}**, role **${role.name}** was added to all members`)
        msg.delete();

}

目前，这只会产生超时错误，这是非常不希望的，所以我需要做同样的事情，但要慢一些：）

Answer 1

你能解释一下吗？如果您要等到所有成员都添加完毕，可以使用：


module.exports.run = async (bot, message, args, level) => {
    if (!args || args.length < 1) return message.reply("Must provide a role to give. Derp.");


    let role = message.guild.roles.find(r => r.name == args[0])

    if (!role) return message.channel.send(`**${message.author.username}**, role not found`)

        let msg = await message.channel.send("Ur lazy")

        const members = message.guild.members.filter(m => !m.user.bot);
     for(let i = 0; i < members.length; i++){
       await new Promise(resolve => setTimeout(() => {
           members[i].addRole(role)
           resolve();
         },1000))
     }



        message.channel.send(`**${message.author.username}**, role **${role.name}** was added to all members`)
        msg.delete();

}

如何绕过.forEach循环，这样我才不会向api发送垃圾邮件？

1 个答案: