Question

我正在尝试通过php脚本将用户个人资料图片从其画廊发送到在线文件系统。我已经确认，除了图片的名称和编码的字符串实际上没有从android应用程序发送到php脚本之外，其他所有操作均正常。我从脚本中获取了回显消息，并确认$ _POST值为空。

我已经确保要发送的信息，尤其是当将其发送到http请求时，其名称不为null。这是我的doInBackground，用于上传图片。 image是他们选择的图像的位图。

protected String doInBackground(String... strings) {
            ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
            image.compress(Bitmap.CompressFormat.JPEG, 100, byteArrayOutputStream);
            String encodedImage = Base64.encodeToString(byteArrayOutputStream.toByteArray(), Base64.DEFAULT );

            ArrayList<NameValuePair> dataToSend = new ArrayList<>();
            dataToSend.add(new BasicNameValuePair("image", encodedImage));
            dataToSend.add(new BasicNameValuePair("name", name));

            HttpParams httpRequestParams = getHttpRequestParams();
            HttpClient client = new DefaultHttpClient(httpRequestParams);
            HttpPost post = new HttpPost(SERVER_ADDRESS);


            try {
                post.setEntity(new UrlEncodedFormEntity(dataToSend));
                client.execute(post);
            } catch (Exception e) {
                e.printStackTrace();
            }

            String result = "";
            String connection = "http://www.myurl.com/uploadprofile.php";
            try {
                URL url = new URL(connection);
                HttpURLConnection http = (HttpURLConnection) url.openConnection();
                InputStream ips = http.getInputStream();
                BufferedReader reader = new BufferedReader(new InputStreamReader(ips, StandardCharsets.ISO_8859_1));
                String line = "";

                while ((line = reader.readLine()) != null) {
                    result += line;
                }
                reader.close();
                ips.close();
                http.disconnect();


            } catch (Exception e) {
                e.printStackTrace();
            }


            return result;
        }

这是php文件

<?php

    $servername = "localhost";
    $username = "username";
    $password = "password";

    $conn = mysqli_connect($servername, $username, $password);

    $name = $_POST['name'];
    $image = $_POST['image'];
    $decodedImage = base64_decode("$image");
    file_put_contents("uploads/".$name.".jpg", $decodedImage);

    echo "entered this file: name-" . $name;

?>

我希望这会上传带有用户名的实际图片。但是，我只是得到一个空的.jpg文件。它应该是username.jpg，并且超过0个字节。

如何使用PHP将图像字符串从Android应用程序发送到文件系统

0 个答案: