Question

我想在Django Restframework中发出API请求，例如 http://localhost:8000/apis/services/?page=1&name=2

模型

from django.contrib.postgres.fields import JSONField

class Service(models.Model):
   name = JSONField(default=dict)

APIView

class DashboardServicesAPIView(ListAPIView):
    queryset = Service.objects.none()
    serializer_class = ServiceSerializer
    permission_classes = (AllowAny,)
    filter_class = ServiceFilter

    def get_queryset(self):
        return Service.objects.filter(vendor__company=self.request.user.userprofile.company)

过滤器集

class ServiceFilter(django_filters.rest_framework.FilterSet):
    name = django_filters.CharFilter(field_name="name", 
lookup_expr='icontains') 
    class Meta:
        model = Service
        fields = [ "name"]

过滤settings.py中的后端

REST_FRAMEWORK = {
'DEFAULT_FILTER_BACKENDS': (
        'django_filters.rest_framework.DjangoFilterBackend',
    ),
.
.
.

使用过滤器querystring的

查询不起作用，总是返回相同的结果。我错过了处理JSON的任何帮助吗？

Answer 1

您需要添加filter_backends才能将django_filter与drf集成

class DashboardServicesAPIView(ListAPIView):
    queryset = Service.objects.none()
    serializer_class = ServiceSerializer
    permission_classes = (AllowAny,)
    filter_class = ServiceFilter

    filter_backends = (filters.DjangoFilterBackend,) 

    def get_queryset(self):
        return Service.objects.filter(vendor__company=self.request.user.userprofile.company)

https://django-filter.readthedocs.io/en/master/guide/rest_framework.html

django-filter库包含DjangoFilterBackend类，该类支持针对REST框架的高度可自定义的字段过滤。

使用django_filters在DRF ListAPIView中的JSONField字段上的FilterSet始终返回相同的结果

1 个答案: