对于一个新项目,我正在使用ReactiveUI。我开始非常喜欢反应式编程背后的想法,但是仍然难以解决一些概念和编写惯用代码的问题。
在此示例中,我有一个非常基本的MainWindow,带有一个名为“ UserId”的文本框:
<Window
x:Class="ReactiveUiDemo.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow"
Width="800"
Height="450">
<StackPanel>
<TextBox x:Name="UserId" />
</StackPanel>
</Window>
TextBox绑定到MainWindow的构造函数中相应视图模型上的属性:
using System.Reactive.Disposables;
using System.Windows;
using ReactiveUI;
namespace ReactiveUiDemo
{
public partial class MainWindow : Window, IViewFor<MainWindowViewModel>
{
public MainWindowViewModel ViewModel { get; set; }
object IViewFor.ViewModel
{
get => ViewModel;
set => ViewModel = (MainWindowViewModel)value;
}
public MainWindow()
{
InitializeComponent();
ViewModel = new MainWindowViewModel();
this.WhenActivated(disposables =>
{
this
.Bind(ViewModel, vm => vm.UserId, v => v.UserId.Text)
.DisposeWith(disposables);
});
}
}
}
此后的ViewModel将观察该属性(将ReactiveUI.Fody [Reactive]属性应用到该属性)。输入4位数字后,它将尝试查找用户,如果UserId为1234,则该用户成功或失败。然后使用MessageBox显示此结果。
using System;
using System.Reactive;
using System.Reactive.Linq;
using System.Threading.Tasks;
using System.Windows;
using ReactiveUI;
using ReactiveUI.Fody.Helpers;
namespace ReactiveUiDemo
{
public sealed class MainWindowViewModel : ReactiveObject
{
[Reactive]
public string UserId { get; private set; }
public MainWindowViewModel()
{
this
.WhenAnyValue(t => t.UserId)
.Where(u => (u?.Length ?? 0) == 4)
.Where(u => int.TryParse(u, out _))
.Select(i => int.Parse(i))
.Select(i => GetUserName(i))
.Match(
userName => DisplaySuccess(userName),
failure => DisplayError(failure))
.Do(_ => UserId = string.Empty)
.Subscribe(
_ => MessageBox.Show("OnNext"),
_ => MessageBox.Show("OnError"),
() => MessageBox.Show("OnCompleted"));
}
private enum Failure { UserNotFound }
private Result<string, Failure> GetUserName(int userId)
{
if (userId == 1234)
return "Waldo";
return Failure.UserNotFound;
}
private async Task<Unit> DisplayError(Failure failure)
{
MessageBox.Show($"Error: {failure}.");
await Task.CompletedTask;
return Unit.Default;
}
private async Task<Unit> DisplaySuccess(string userName)
{
MessageBox.Show($"Found {userName}!");
await Task.CompletedTask;
return Unit.Default;
}
}
}
“结果”类(或此结果的剥离版本)包含TSuccess或TFailure:
using System;
namespace ReactiveUiDemo
{
public sealed class Result<TSuccess, TFailure>
{
private readonly bool _isSuccess;
private readonly TSuccess _success;
private readonly TFailure _failure;
private Result(TSuccess value)
{
_isSuccess = true;
_success = value;
_failure = default;
}
private Result(TFailure value)
{
_isSuccess = false;
_success = default;
_failure = value;
}
public TResult Match<TResult>(Func<TSuccess, TResult> successFunc, Func<TFailure, TResult> failureFunc)
=> _isSuccess ? successFunc(_success) : failureFunc(_failure);
public static implicit operator Result<TSuccess, TFailure>(TSuccess value)
=> new Result<TSuccess, TFailure>(value);
public static implicit operator Result<TSuccess, TFailure>(TFailure value)
=> new Result<TSuccess, TFailure>(value);
}
}
让我头疼的扩展方法是Match方法,其定义如下:
using System;
using System.Reactive.Linq;
using System.Reactive.Threading.Tasks;
using System.Threading.Tasks;
namespace ReactiveUiDemo
{
public static class ObservableExtensions
{
public static IObservable<TResult> Match<TSuccess, TFailure, TResult>(
this IObservable<Result<TSuccess, TFailure>> source,
Func<TSuccess, Task<TResult>> success,
Func<TFailure, Task<TResult>> failure)
=> Observable.FromAsync(async () => await source.SelectMany(result => result.Match(success, failure).ToObservable()));
}
}
在Match扩展方法之前,代码将按预期工作。 DisplayError或DisplaySuccess被调用,但这已经结束了。 Do和Subscribe中的操作未执行。我相信我的Match扩展方法存在问题,但我不知道如何解决。
作为旁注,我想有一种更好的方式来编写此位:
.Where(u => (u?.Length ?? 0) == 4)
.Where(u => int.TryParse(u, out _))
.Select(int.Parse)
我可以想象使用TryParseInt扩展方法,但是也许不需要它吗?
修改
根据@GlennWatson的回答更新了扩展方法,它现在可以正常运行了:
public static IObservable<TResult> Match<TSuccess, TFailure, TResult>(
this IObservable<Result<TSuccess, TFailure>> source,
Func<TSuccess, Task<TResult>> success,
Func<TFailure, Task<TResult>> failure)
=> source.SelectMany(r => r.Match(success, failure).ToObservable());
答案 0 :(得分:1)
FromAsync()方法仅用于基于任务的系统。
在使用Observable和后续的Linq样式方法时,请尝试使其尽可能保持Observable形式。
在您的示例中,您正在等待一个Observable并将其包装在FromAsync中。 SelectMany有一个重载,它了解基于任务的操作。