我在src / main / resources(/ resources / files / templates)中有一个Excel文件。我想将其读取到InputStream。我没有为此找到合适的语法。
componentDidMount(){
if(Platform.OS === 'ios'){
navigator.geolocation.requestAuthorization()
}
//state for opened toggle and combine with android platform
else if (Platform.OS === 'android') {
async function requestlocationPermission() {
try {
const granted = await PermissionsAndroid.request(
PermissionsAndroid.PERMISSIONS.ACCESS_FINE_LOCATION,
{
title: 'Location permission',
message:
'Just for location ',
buttonNegative: 'Cancel',
buttonPositive: 'OK',
},
);
if (granted === PermissionsAndroid.RESULTS.GRANTED) {
console.log('location enabled');
} else {
console.log('location denied');
}
} catch {
console.warn(err)
}
}
setInterval(requestlocationPermission(), 2500)
}
}
以上操作无效。我认为路径是错误的。如何为存储在资源中的文件提供正确的路径?
答案 0 :(得分:0)
这个对我有用。
InputStream is = YourClass.class.getClassLoader().getResourceAsStream("relative path to your file starting from resources folder");
答案 1 :(得分:0)
如果您使用任何方法(静态或非静态):
String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
InputStream in = Clazz.class.getResourceAsStream(fn);
Clazz
是您所在的班级的名称。
如果您使用的是非静态方法:
String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
InputStream in = getClass().getResourceAsStream(fn);