有没有一种有效的方法来在Django中执行搜索查询?

时间:2019-07-05 08:16:11

标签: python django sqlite search

我正在创建一个博客,我希望在该博客中根据评分(1-5)进行搜索查询。在这里,我的搜索就像查询:“智能手机技术更新”,等级:“ 3”。结果应该是包含val排序方式为3的查询词(至少一个词)的帖子列表(至少一个单词)(在val(对于每个查询词,如果在标题val + = 1中找到,如果在内容val + = 0.4中找到))。

我的models.py文件具有以下内容:

class Post(models.Model):
    title = models.CharField(max_length=50)
    content = models.CharField(max_length=500)
    rating = models.IntegerField(default=1)
    enter code here
    date = models.DateTimeField(default=timezone.now)
    author = models.ForeignKey(User, on_delete=models.CASCADE)

我的view.py文件具有以下内容:

def search(request):
    contents = Post.objects.all()

    if request.method == 'GET':
        query = request.GET['query']
        rating = request.GET['rating']

        # search function

        # contents = InSearch.search_fun(contents,query,rating)
        vector = SearchVector('title', weight='A') + SearchVector('content', weight='B')
        qry = SearchQuery(str(query))
        contents = Post.objects.annotate(rank=SearchRank(vector, qry)).order_by('-rank')

        #print("---->\n\t"+query+ str(contents))

        context = {
            'contents': contents
        }
    else:
        context = {
            'contents': Post.objects.all()
        }

    return render(request, 'feed/home.html', context)

我的urls.py是:

urlpatterns = [
    #...
    path('feed/search-result/', views.search, name='feed_search'),
]

我收到此错误 django.db.utils.OperationalError: no such function: plainto_tsquery

1 个答案:

答案 0 :(得分:1)

您可以在视图中尝试这样进行搜索。

from django.db.models import Q
def search(request):
 q = request.GET.get('q')
    if q:
       search_results = Post.objects.filter(Q(title__icontains=q)|Q(rating=q))
   # if you want the exact then do Post.objects.filter(Q(title__iexact=q) & Q(rating=q))

       return render(request, 'feed/home.html','search_results':search_results)
    else:
        messages.info(request,'no results found for {}',format(q))

如果您要按匹配数对搜索查询结果进行排序,则可以这样尝试:

search_results = Post.objects.filter(Q(title__icontains=q)|Q(rating=q)).annotate(title_counts=Count('title')).order_by('-title_counts')

然后在您的模板中的搜索表单中输入name='q'

 <form  action="{% url 'your search action' %}">
     <input type="text" name="q">
     <input type='submit' value='Search'>
   </form>