比较两个列表列表，并在保持结构的同时仅保留匹配的元素

Question

给出以下两个嵌套列表：

circuitBreaker.protect(task).runSyncMaybe

我正在尝试按列表比较两个列表，同时保持列表结构，仅保留匹配项：

alist = [[1,4,10,2], [4,1,12,10], [5,12,4,10], [5,10,2,4]]

blist = [[2,4,10,9,13,20], [12,9,20,33,Not,15], [3,1,2,7,4,8], [Not,9,8,3,4,5]]

预先感谢您的帮助！

Answer 1

您可以使用set.intersection()（doc）：

Not = object()

alist = [[1,4,10,2], [4,1,12,10], [5,12,4,10], [5,10,2,4]]

blist = [[2,4,10,9,13,20], [12,9,20,33,Not,15], [3,1,2,7,4,8], [Not,9,8,3,4,5]]

new_list = [list(set(i).intersection(j)) for i, j in zip(alist, blist)]
print(new_list)

打印：

[[2, 10, 4], [12], [4], [4, 5]]