我有此代码
<?php
class Objekt{
// database connection and table name
private $conn;
private $table_name = "objects";
// object properties
public $id;
public $id_group;
public $title;
public $description;
public $lat;
public $lng;
public $icon;
public $tagsraw;
// constructor with $db as database connection
public function __construct($db){
$this->conn = $db;
}
function create(){
// query to insert record
$query = "INSERT INTO
" . $this->table_name . "
SET
id_group=:id_group, title=:title, description=:description, lat=:lat, lng=:lng, icon=:icon;
SELECT max(id) AS id FROM objects;";
// prepare query
$stmt = $this->conn->prepare($query);
// sanitize
$this->id_group=htmlspecialchars(strip_tags($this->id_group));
$this->title=htmlspecialchars(strip_tags($this->title));
$this->description=htmlspecialchars(strip_tags($this->description));
$this->lat=htmlspecialchars(strip_tags($this->lat));
$this->lng=htmlspecialchars(strip_tags($this->lng));
$this->icon=htmlspecialchars(strip_tags($this->icon));
// bind values
$stmt->bindParam(":id_group", $this->id_group);
$stmt->bindParam(":title", $this->title);
$stmt->bindParam(":description", $this->description);
$stmt->bindParam(":lat", $this->lat);
$stmt->bindParam(":lng", $this->lng);
$stmt->bindParam(":icon", $this->icon);
// execute query
if($stmt->execute()){
//$stmt->execute();
/*
ERROR below here
Uncaught PDOException: SQLSTATE[HY000]: General error
stack trace:
#0 PDOStatement ->fetch(2)
#1 Objekt->create()
*/
$result = $stmt->fetch(PDO::FETCH_ASSOC);
$this->id = $result['id'];
echo "$this->id";
//get tags matches
$tags = [];
$this->tagsraw = preg_replace('/\s+/', '', $this->tagsraw);
$tags = explode(',', $this->tagsraw);
$id_tags = [];
for ($i = 0; $i < sizeof($tags); $i++) {
$query = "SELECT id FROM category WHERE title=" . tags[i];
$stmt = $this->conn->prepare($query);
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_OBJ);
$id_tags[i] = $result->id;
}
for ($i = 0; $i < sizeof($id_tags); $i++) {
$query = "INSERT INTO category_object SET id_object=" . $this->id . ", id_category=" . $id_tags[i];
$stmt = $this->conn->prepare($query);
$stmt->execute();
}
return true;
}
return false;
}
我想做什么:
插入对象并通过外键id_object / id_category创建与category_object表的关系
我想改进的地方:
如果插入失败,我该怎么做(我应该在哪里放置try / catch或其他方法)
我的提取有什么问题?我从max(id)中选择值以获取插入的对象的值,为什么会抛出异常
我还有另一个警告,为什么它告诉我
for ($i = 0; $i < sizeof($id_tags); $i++) {
$query = "INSERT INTO category_object SET id_object=" . $this->id . ", id_category=" . $id_tags[i];
$stmt = $this->conn->prepare($query);
$stmt->execute();
}
将在以后的php版本中弃用。.
答案 0 :(得分:1)
使用transactions。
在事务中完成的任何插入/更新/删除操作都不会在数据库上实际执行,除非您调用sn -i D:\XX\MYProject.UI.api\MYProject.Gateway\my_certificate.pfx VS_KEY_AD6FD8AFB39B6C43
,并且您始终可以回滚更改,以防失败时放弃更改。
在您的代码中,您可以将
替换为commit()
if($stmt->execute()){