Question

我开始学习Python，我想知道你们能否为我的问题提供一些帮助/改善我的编码。这段代码基本上是一个登录屏幕，当您输入正确的用户名和密码时，它将解锁可访问的url列表。但是，当用户输入一个大于4的值时，我很难找到一种使它“回送”的方法。

import webbrowser
import time

print("Enter Username")
name = input()

while name != 'Admin':
    print("Invalid Username")
    name = input()

if name == 'Admin':
    print("Enter Password")

password = input()

while password != 'Password':
    print("Incorrect Password")
    password = input()

if password == 'Password':
    print("Login Successful")

if name == 'Admin' and password == 'Password':
    time.sleep(1)
    print("Which Webpage would you like to visit? Select Value")
    time.sleep(1)
    print("0. Python Library")
    print("1. ASTA Homepage")
    print("2. Autotask Homepage")
    print("3. Google")
    print("4. Youtube")

webpage = input()

if webpage == '0':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('http://www.blog.pythonlibrary.org')

if webpage == '1':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.asta.com.au/')

if webpage == '2':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://ww6.autotask.net')

if webpage == '3':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.google.com.au')

if webpage == '4':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.youtube.com')

Answer 1

更改以下部分：

webpage = input()

if webpage == '0':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('http://www.blog.pythonlibrary.org')

if webpage == '1':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.asta.com.au/')

if webpage == '2':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://ww6.autotask.net')

if webpage == '3':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.google.com.au')

if webpage == '4':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.youtube.com')

收件人：

webpage = input()
while int(webpage) > 4:
    webpage = input()
if webpage == '0':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('http://www.blog.pythonlibrary.org')

if webpage == '1':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.asta.com.au/')

if webpage == '2':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://ww6.autotask.net')

if webpage == '3':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.google.com.au')

if webpage == '4':
    print("Excellent Choice")
    time.sleep(2)
    webbrowser.open('https://www.youtube.com')

Answer 2

这有效

webpage = input()

while not webpage.isdecimal() or int(webpage) not in range(0, 5):
    print("unacceptable number.")
    webpage = input()

print("Excellent Choice")
time.sleep(2)
webbrowser.open(['http://www.blog.pythonlibrary.org', 'https://www.asta.com.au/', 'https://ww6.autotask.net', 'https://www.google.com.au', 'https://www.youtube.com'][int(webpage)]

如何使网页！=的值大于5？

2 个答案: