如果C ++中有多个继承模板,则非法调用非静态成员函数

时间:2019-07-04 02:40:04

标签: c++ templates inheritance crtp

我有一个具有2个策略的主机,每个策略都有一个print函数。 如果我致电Policy::print(),就没有问题,但是如果我致电OtherPolicy::print(),则会收到错误消息。

Error   C2352    'OtherPolicy<T,Host<T,SubPolicy,OtherPolicy>>::printer': illegal call of non-static member function
        with
        [
            T=uint32_t
        ]   Scratch D:\tmp\ScratchCpp\Scratch\Scratch\HostPolicy.h  63  
#include <iostream>

template<
    typename T,
    class Host
>
class Policy {
public:
    virtual void printer()
    {
        std::cout << "base policy" << std::endl;
    }
};

template<
    typename T,
    class Host
>
class SubPolicy : Policy<T, Host> {
public:
    void printer() override
    {
        auto host = static_cast<Host&>(*this);
        std::cout << "sub policy" << std::endl;
    }
};

template<
    typename T,
    class Host
>
class OtherPolicy {
public:
    void printer()
    {
        auto host = static_cast<Host&>(*this);
        std::cout << "other policy" << std::endl;
    }
};

template<
    typename T,
    template<typename, class> class A,
    template<typename, class> class B
>
class Host :
    public A<T, Host<T, A, B>>,
    public B<T, Host<T, Policy, B>> {
public:
    void printer()
    {
        std::cout << "host" << std::endl;
        A<T, Host>::printer();
        B<T, Host>::printer(); // comment out this line to compile successfully
    }
};

int main(int argc, char **argv)
{
    Host<uint32_t, SubPolicy, OtherPolicy> host;
    host.printer();
}

有人会好心地解释正在发生的事情以及如何正确执行此操作吗?

1 个答案:

答案 0 :(得分:2)

Host的第二个基类的类型为B<T, Host<T, Policy, B>>,不是 B<T, Host>。由于B<T, Host>不是Host的基类,因此会导致错误。

解决方法是正确命名基类的类型:

B<T, Host<T, Policy, B>>::printer();