Question

我想在AES中加密和解密“ ABCD1234”，但输出不相同。要获得相同的结果我该怎么做？

使用crypto-js加密

function encrypt(string) {
  const key = CryptoJS.enc.Utf8.parse("g@eNR@2H'9n/ZF8s");
  const encrypted = CryptoJS.AES.encrypt(string, key, {
    iv: CryptoJS.enc.Utf8.parse("Fa6Fy$F8.qRvHKU+"),
    mode: CryptoJS.mode.CBC,
    padding: CryptoJS.pad.NoPadding
  });
  return encrypted.toString()
}

document.getElementById("encrypted").innerHTML = encrypt("ABCD1234");

则输出为sRdk5O4U + WA =

当我尝试在Java中解密

import java.util.Base64;
import javax.crypto.Cipher;
import javax.crypto.spec.SecretKeySpec;
import javax.crypto.spec.IvParameterSpec;

class Main {
  public static void main(String[] args) {
        String data = "sRdk5O4U+WA=";
        String key = "g@eNR@2H'9n/ZF8s";
        String iv = "Fa6Fy$F8.qRvHKU+";
        try 
        {
            byte[] encrypted1  = Base64.getDecoder().decode(data);
            Cipher cipher = Cipher.getInstance("AES/CBC/NoPadding");
            SecretKeySpec keyspec = new SecretKeySpec(key.getBytes("UTF-8"), "AES");
            IvParameterSpec ivspec = new IvParameterSpec(iv.getBytes("UTF-8"));
            cipher.init(Cipher.DECRYPT_MODE, keyspec, ivspec);


            byte[] original = cipher.doFinal(encrypted1);

            String decrypt = new String(original).trim();
            System.out.println("decrypt "+decrypt);
        } catch (Exception e)
        {
            System.out.println("e "+e.toString());
        }
  }
}

抛出异常javax.crypto.IllegalBlockSizeException：输入长度不是16个字节的倍数

java代码：https://repl.it/repls/NoxiousWavyMp3

javascript代码：https://codepen.io/anon/pen/ydEpZB

javascript中的AES加密问题以及java

0 个答案: