Question

错误是致命错误：在第72行的/home/mjcrawle/public_html/cit0215/assignment5/onlinebanking/viewaccounts.php中调用未定义的方法stdClass :: retrieve_all_accounts（）

我没有收到任何HTML错误，所以我会把它留下来。

我的PHP代码错误是：

<?php 

require_once('footer_nav/navigation.inc.php'); 
require_once('../websiteconfig.inc.php');
require_once('../class/person_class.php');
require_once('../class/database.class.php');

/*Start Session*/
session_start();

$currentMember =unserialize($_session['currentMember']);

/*DataBase*/
$db = new Database;
$conn = $db->connection;
?>
<td width="16">&nbsp;</td>
<td width="595">
</td>
</tr>

</div>


<h2>Accounts</h2>  


</td>
<table id="accounts" summary="Bank Account Balance Information">
<thread>
    <tr>
        <th>Account Number</th>
        <th>Account Balance</th>
     </tr>
  </thead> 
<tbody>     
<php?
/*Accounts*/
$currentMember->connection = $conn;

这是我得到错误行72的地方：

$accounts = $currentMember->retrieve_all_accounts();

/* Loop Though Accounts*/
while($account = mysqli_fetch_assoc($account)) {
    /* Retrieve Account Balance*/
$bankaccount = new Bankaccount ($account['BankAccountID']);
$bankaccount->connection = $conn;
$balance = mysqli_fetch_assoc($bankaccount->retrieve_current_balance());

 echo '<tr>' . "\n";
 echo "\t" . '<td class="account_number">' . $account['BankAccountID'] . '</td>' . "\n";
 echo "\t" . '<td class="account_balance">$' .   number_format($balance['CurrentBalance'], 2) . '</td>' . "\n";
 echo '</tr>' . "\n";

}

/*Closed DataBase*/ 
mysqli_close($db->connection);

?>

Answer 1

首先，您在第一部分代码中使用了这个：

<php?
/*Accounts*/
$currentMember->connection = $conn;

如果您真的复制粘贴了这个，那么这里有一个问题：这不是PHP代码。

相反，你应该：

<?php
/*Accounts*/
$currentMember->connection = $conn;

请注意，PHP开头标记为<?php而不是<php?

然后，您的$currentMember变量以这种方式设置：

$currentMember =unserialize($_session['currentMember']);

这似乎只会在容器上生成$currentMember，而不是具有retrieve_all_accounts()方法的类的实例。

因此，在尝试调用该方法时：

$accounts = $currentMember->retrieve_all_accounts();

您收到致命错误，因为$currentMember对象中没有此类方法。

PHP BD错误行72

1 个答案: