“如何用django编写”

时间:2019-07-03 10:33:49

标签: django

我想这样在 django 模板中编写代码:

for i in range(6):
    if i%2==0:
        print i, i+1

    <table class="pp-choice-careers">
    <caption>Parent's Choice for Interest Careers</caption>
    <tr><th>Careers</th><th>Why this career</th></tr>
    {% for career in resultArr.parent_choice_career %}
    <tr class="pp-class">
    {% if forloop.counter|mod:2 == 0 %}
    <td>{% if career == 'NA' %}Not Available{% else %} . {{career.answer}}{% endif %}</td>
    {% else %}
    <td>{% if career == 'NA' %}Not Available{% else %}{{career.answer}}{% endif %}</td>
    {% endif %}
     </tr>
{% endfor %}
</table>

我想从两行中的列表中打印两个值,所以我需要在current+1部分使用else索引。

0 个答案:

没有答案