Question

所以问题出在9到32行。它输出说“ 3 0 0”，然后是“ 3 4 0”，然后是“ 3 4 6”。而是应该说“ 3 4 6”，然后可以是“ 6 1 2”。我知道这与numRolled变量以及该变量的循环方式有关，但我想不起来还要把它放在哪里。

我尝试将numRolled = 0放在“ for i in range（3）”的末尾，但这只能使第一个数字发生变化。我曾尝试将数字放入单个变量列表中，但我对列表编码并不十分有信心，因此我决定继续使用此处的内容。

def DiceGame():

  numRolled = 1
  RunScore = 0
  Roll1 = 0
  Roll2 = 0
  Roll3 = 0
  #rolls the 3 dice 100 times
  for x in range(100): 
    numRolled = 0
    #rolls the 3 dice
    for i in range(3):
      score = rdm.randint(1,6)
      numRolled += 1
      #assigns score to each die
      if numRolled == 1:
        Roll1 = score
      if numRolled == 2:
        Roll2 = score
      if numRolled == 3:
        Roll3 = score

      if Roll1 == Roll2 and Roll1 == Roll3:
        RunScore += 100
      else:
        DiceTot = Roll1 + Roll2 + Roll3
      # If Total of Die MOD 2 == 0 then Running score += Dice Total 
      if DiceTot % 2 == 0:
        RunScore += DiceTot
      else:
        RunScore -= DiceTot  
      print(Roll1, Roll2, Roll3)
      print(RunScore)

如上所述，它输出说“ 3 0 0”然后“ 3 4 0”然后“ 3 4 6”。而是应该说“ 3 4 6”，然后可能是“ 6 1 2”

Answer 1

更改此

def game: 
    forlopp:
        forloop:
            print()
            print()

对此

def game: 
    forlopp:
        forloop:
        print()
        print()

Answer 2

将与单个骰子无关的所有内容移出第一个循环：

Function Loss(worksheet1 As Worksheet) As Long
    Dim min As Double
    Dim i As Integer
    Dim myRight As Long, Colcount As Long

    min = 0

    myRight = ActiveSheet.Cells(1, ActiveSheet.Columns.Count).End(xlToLeft).Column

    For Colcount = 1 To myRight
        If (ActiveSheet.Cells(11, Colcount) > min) And Abs(ActiveSheet.Cells(11, Colcount) <= 100) Then
            min = ActiveSheet.Cells(11, Colcount)
        End If
        Exit For
    Next Colcount
End Function

那应该修复代码。

但是，使用列表会更容易。您可以像这样生成3个掷骰子的列表：

  for x in range(100): 
    numRolled = 0
    #rolls the 3 dice
    for i in range(3):
      score = rdm.randint(1,6)
      numRolled += 1
      #assigns score to each die
      if numRolled == 1:
        Roll1 = score
      if numRolled == 2:
        Roll2 = score
      if numRolled == 3:
        Roll3 = score

    ####
    # Here the code below has been un-indented and removed from the range(3) loop
    ####

    if Roll1 == Roll2 and Roll1 == Roll3:
      RunScore += 100
    else:
      DiceTot = Roll1 + Roll2 + Roll3


      #####
      # Note: I have indented the following block to put it inside
      #       this "else" clause, so that it can use "DiceTot" reliably.
      #####

      # If Total of Die MOD 2 == 0 then Running score += Dice Total 
      if DiceTot % 2 == 0:
        RunScore += DiceTot
      else:
        RunScore -= DiceTot  
    print(Roll1, Roll2, Roll3)
    print(RunScore)

也可以将其写为列表理解：

rolls = []
for _ in range(3):
  rolls.append(rdm.randint(1,6))

无论您做什么，都可以更轻松地生成统计信息：

rolls = [rdm.randint(1,6) for _ in range(3)]

您可以使用if all(roll == rolls[0] for roll in rolls): RunScore += 100 else: DiceTot = sum(rolls) if DiceTot % 2 == 0: RunScore += DiceTot else: RunScore -= DiceTot函数进行打印：

join

使用这样的列表将使您摆脱3个骰子掷骰子变量，并无需更改任何内容即可随意更改骰子掷骰子次数。

我正在尝试制作骰子游戏，以使它不会改变每次掷骰子的数目，而是会改变所有骰子的数目

2 个答案: