Question

我正在尝试为应用创建登录页面，但我认为

if ($_SERVER['REQUEST_METHOD']=='POST')

满足条件。

我不确定这是由php还是android代码的问题引起的，因为我使用相同的代码进行了有效的注册活动。我想知道密码散列是否可能有问题？

登录时，尽管没有出现成功登录的提示，但进度栏仍会弹出。我不确定问题出在哪里，任何帮助将不胜感激。

带有if语句的php代码：

<?php

if ($_SERVER['REQUEST_METHOD']=='POST'){
    require 'conn.php';

    $email = $_POST['email'];
    $password = $_POST['password'];


    $sql = "SELECT * FROM Patients WHERE email = '$email'";

    $response = mysqli_query($conn, $sql);



    $result = array();
    $result["login"] = array();

    if (mysqli_num_rows($response) === 1 ) {

        $row = mysqli_fetch_assoc($response);

        if (password_verify($password, $row['password']) ) {


            $index['name'] = $row['name'];
            $index['email'] = $row['email'];

            array_push($result['login'], $index);

            $result['success'] = "1";
            $result['message'] = "success";
            echo json_encode($result);

            mysqli_close($conn);


        } else {

            $result['success'] = "0";
            $result['message'] = "error";
            echo json_encode($result);

            mysqli_close($conn);

        }

    }

}

?>

Java JSON解析代码：

private void Login(final String email, final String password) {

        loading.setVisibility(View.VISIBLE);
        btnLogin.setVisibility(View.GONE);

        StringRequest stringRequest = new StringRequest(Request.Method.POST, URL_LOGIN,
                new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {
                        try {
                            JSONObject jsonObject = new JSONObject(response);
                            String success = jsonObject.getString("success");
                            JSONArray jsonArray = jsonObject.getJSONArray("login");
                            if(success.equals("1")){
                                for(int i = 0;i<jsonArray.length();i++){

                                    JSONObject object = jsonArray.getJSONObject(i);
                                    String name = object.getString("name").trim();
                                    String email = object.getString("email").trim();

                                    Toast.makeText(Main2Activity.this, "Success login. \nYour name : "+name+"\nYour Email : "+email, Toast.LENGTH_SHORT).show();

                                    loading.setVisibility(View.GONE);

                                }
                            }
                        } catch (JSONException e) {
                            e.printStackTrace();
                            loading.setVisibility(View.GONE);
                            btnLogin.setVisibility(View.VISIBLE);
                            Toast.makeText(Main2Activity.this, "Error"+e.toString(), Toast.LENGTH_SHORT).show();
                        }
                    }
                },
                new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        loading.setVisibility(View.GONE);
                        btnLogin.setVisibility(View.VISIBLE);
                        Toast.makeText(Main2Activity.this, "Error"+error.toString(), Toast.LENGTH_SHORT).show();


                    }
                })
        {
            @Override
            protected Map<String, String> getParams() throws AuthFailureError {
                Map<String, String> params = new HashMap<>();
                params.put("email", email);
                params.put("password", password);


                return params;
            }
        };

        RequestQueue requestQueue = Volley.newRequestQueue(this);
        requestQueue.add(stringRequest);

    }



}

我没有收到任何错误消息，因此我认为onResponse方法无效。而是显示进度条，什么也没有发生。

如果不满足（$ _SERVER ['REQUEST_METHOD'] =='POST'）条件

0 个答案: