分割定界符

Question

我有两个表Table A和TableB。我需要在Table A中的表B中添加电子邮件ID列。

例如，

表A

表B

预期结果：

Answer 1

尝试以下操作：

declare @table_A table (username varchar(1000))
declare @table_B table (username varchar(1000), email_id varchar(2000))

insert into @table_A
select 'User, AA # User, BB'
union
select 'User, CC # User, DD # User, EE'
union
select 'User, FF # User, GG # User, HH'

insert into @table_B
select 'User, AA','User.a@gmail.com'
union
select 'User, BB','User.b@gmail.com'
union
select 'User, CC','User.c@gmail.com'
union
select 'User, DD','User.d@gmail.com'
union
select 'User, EE','User.e@gmail.com'
union
select 'User, FF','User.f@gmail.com'
union
select 'User, GG','User.g@gmail.com'
union
select 'User, HH','User.h@gmail.com'

select A.username, B.email_id into #temp
from
(
    select username, ltrim(rtrim(value)) val
    from @table_A
    cross apply string_split(username, '#') 
)A
left join @table_B B on B.username = A.val  

select username, ltrim(rtrim(stuff((
        select DISTINCT ' # ' + u.email_id
        from #temp u
        where u.username = t.username
        for xml path('')
    ),2,1,''))) as email_id
from #temp t
group by username

drop table if exists #temp

Answer 2

使用STUFF函数的另一种方式可能会很有趣

declare @TableA table (username varchar(1000))
declare @TableB table (username varchar(1000), email_id varchar(2000))

insert into @TableA values
('User, AA # User, BB'),('User, CC # User, DD # User, EE'),('User, FF # User, GG # User, HH')

insert into @TableB values
('User, AA','User.a@gmail.com'),('User, BB','User.b@gmail.com'),('User, CC','User.c@gmail.com'),
('User, DD','User.d@gmail.com'),('User, EE','User.e@gmail.com'),('User, FF','User.f@gmail.com'),
('User, GG','User.g@gmail.com'),('User, HH','User.h@gmail.com')

;with ct as (
select a.username, b.email_id
from @TableB b
    inner join @TableA a on charindex(b.username, a.username) > 0
)
select username, abc = STUFF 
(
    (
        SELECT ' # ' + email_id
        FROM ct As t2
        WHERE t2.username = t1.username
        ORDER BY username
        FOR XML PATH (''), TYPE
    ).value('.', 'varchar(max)')
, 1, 1, '')
from ct t1
group by username

结果