Question

在条件为真时如何中断while循环？

我尝试在if语句下使用break，但是它不起作用。

def proallocate():
    while True:    
        conn = sqlite3.connect('database.db')
        cur = conn.cursor()
        pid = cur.execute("SELECT project_id FROM Upload WHERE status= ?", ("NULL",))
        for pd in pid:
            a = str(pd)
            projectid = re.sub('[\(\),\{\}<>]', '', a)
            url = "https://picture-us.amazon.com/colorauthor/view/"+projectid+""
            print(url)
            req = requests.Session()
            resp = req.get(url, auth=HTTPKerberosAuth(mutual_authentication=False), verify="./amazon_dev_certs.pem")
            soup = BeautifulSoup(resp.text, 'html.parser')
            project_status_latest = soup.find_all('tr')[-1].get_text()
            if ("Project Ready" in project_status_latest):
                proid[0] = projectid
                print(proid[0])

            else:
                cur.execute("UPDATE Upload SET status = ? WHERE project_id = ?", ("Reserved", projectid))
                conn.commit()

我希望if条件通过时循环应该停止。

Answer 1

这是您可以做的事情的简化版本：

condition = True
while condition:
    for i in range(10):
        print(i)
        if i == 3:
            condition = False
            break

break将中断for循环，而设置condition = False将导致while循环停止。

，您确定要在conn = sqlite3.connect('database.db')循环中while吗？

Answer 2

    q = True
    while q:    
        conn = sqlite3.connect('database.db')
        cur = conn.cursor()
        pid = cur.execute("SELECT project_id FROM Upload WHERE status= ?", ("NULL",))
        for pd in pid:
            a = str(pd)
            projectid = re.sub('[\(\),\{\}<>]', '', a)
            url = "https://picture-us.amazon.com/colorauthor/view/"+projectid+""
            print(url)
            req = requests.Session()
            resp = req.get(url, auth=HTTPKerberosAuth(mutual_authentication=False), verify="./amazon_dev_certs.pem")
            soup = BeautifulSoup(resp.text, 'html.parser')
            project_status_latest = soup.find_all('tr')[-1].get_text()
            if ("Project Ready" in project_status_latest):
                proid[0] = projectid
                q = False
                break
            else:
                cur.execute("UPDATE Upload SET status = ? WHERE project_id = ?", ("Reserved", projectid))
                conn.commit()
                break


it worked

当条件为真时如何打破？

2 个答案: