尊敬的专家们,我有SOAP Env的输入请求,该请求只需要使用XSLT捕获即可 同时,需要删除元素上的名称空间以及每个元素的名称空间前缀。
输入请求
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd"
xmlns:v1="http://xmldefs. ag.com/Applications/eer/V1">
<SOAP-ENV:Header/>
<SOAP-ENV:Body>
<v1:ProcessDistr xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<v1:Group xmlns:ns2="http://xmldefs.ag.com/DD/Commons">
<v1:GroupID>437848</v1: GroupID>
<v1:Status>true</v1:Status>
<v1:Parent>45434554</v1:Parent>
</v1:Group>
</v1:ProcessDistr>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
已收到输出
<?xml version="1.0" encoding="UTF-8"?>
<v1:ProcessDistr xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:wsu=http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:v1="http://xmldefs. ag.com/Applications/eer/V1">
<v1:Group xmlns:ns2="http://xmldefs.ag.com/DD/Commons">
<v1:GroupID>437848</v1: GroupID>
<v1:Status>true</v1:Status>
<v1:Parent>45434554</v1:Parent>
</v1:Group>
</v1:ProcessDistr>
XSLT代码
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:v1="http://xmldefs. ag.com/Applications/eer/V1" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsltc="http://xml.apache.org/xalan/xsltc" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:sap="http://www.sap.com/sapxsl" xmlns:prof="http://ixult.net/ProfileExchange" exclude-result-prefixes ="v1" xmlns:wsu=http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" >
<!-- Output -->
<xsl:output encoding="UTF-8" indent="yes" method="xml" omit-xml-declaration="yes"/>
<xsl:template match="/">
<!-- filter ProcessDistr-->
<xsl:copy-of select="//v1:ProcessDistr"/>
</xsl:template>
</xsl:stylesheet>
我期望这个输出
<?xml version="1.0" encoding="UTF-8"?>
<ProcessDistr >
<Group >
<GroupID>437848</GroupID>
<Status>true</Status>
<Parent>45434554</Parent>
</Group>
</ProcessDistr>
请您分享一下我对此的看法。
非常感谢您。
致以最诚挚的问候, 卫星N
答案 0 :(得分:0)
您想要的结果可以通过以下方式轻松实现:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:v1="http://xmldefs.ag.com/Applications/eer/V1">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="v1:*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="@*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
演示(从输入中删除多余的空格后):https://xsltfiddle.liberty-development.net/pPzifqc
答案 1 :(得分:-1)
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd"
xmlns:v1="http://xmldefs. ag.com/Applications/eer/V1"
xmlns:ns2="http://xmldefs.ag.com/DD/Commons"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
exclude-result-prefixes="xs SOAP-ENV wsu v1 ns2 xsi"
version="2.0">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="SOAP-ENV:Envelope">
<xsl:apply-templates select="SOAP-ENV:Body/v1:ProcessDistr"/>
</xsl:template>
<xsl:template match="v1:ProcessDistr">
<xsl:element name="ProcessDistr">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="v1:Group">
<xsl:element name="Group">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="v1:GroupID">
<xsl:element name="GroupID">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="v1:Status">
<xsl:element name="Status">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="v1:Parent">
<xsl:element name="Parent">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Try this