Question

这是已经在mysql数据库中运行的代码，但我想将其转换为 Laravel 5.6

    SELECT * 
    FROM `listings` 
    WHERE (
    country_id=1 
    AND (state=32 or city=8) 
    AND (listing_id LIKE "%6562%" OR title LIKE "%6562%"))

Answer 1

假设您有一个名为autoIncrement.initialize(mongoose); var districtSchema=new Schema({ _id : {type: Schema.Types.Number, unique: true}, district_name : {type: String, unique: true}, cities : [{type: Schema.Types.Number, ref:'City'}] }, {timestamps:{createdAt:'created_at',updatedAt:'updated_at'}}); districtSchema.plugin(autoIncrement.plugin, {model:'District',field:'_id',startAt:100,incrementBy:1}); var District=mongoose.model('District',districtSchema);的模型，该模型负责处理Listing表。您可以这样编写查询：

listings

$listings = App\Listing::where('field1', 1) ->where(function ($query) { $query->where('field2', 32); $query->orWhere('field3', 8); }) ->where(function ($query) { $query->where('field4', 'LIKE', '%6562%'); $query->orWhere('field5', 'LIKE', '%6562%'); }) ->get();方法的第一个参数可以是可以实现这种分组方式（field2 = 32或field3 = 8）的回调

没有得到正确的结果，但在SQL中工作

1 个答案: