我是React Native的新手,所以我决定实现一个小型Twitter应用程序。但是我被困在某个地方。如下所示,我有一个名为Posty的组件,其中包含一个StackNavigator。屏幕是PostScreen和NewPostScreen。单击PostScreen屏幕标题中的图标时,可以导航到NewPostScreen以编写新的推文。当我编写推文并单击NewPostScreen中的按钮时,它导航回到PostScreen,但是我的新推文未显示。我想再次进行API调用以加载我的新推文。
我已经阅读了React Native(https://reactnavigation.org/docs/en/navigation-lifecycle.html)的文档“ Navigation lifecycle”。它说:“考虑具有屏幕A和B的堆栈导航器。导航到A后,将调用其componentDidMount。按下B时,还将调用其componentDidMount,但是A仍安装在堆栈上,因此不调用其componentWillUnmount。从B返回到A,将调用B的componentWillUnmount,但是A的componentDidMount并不是因为A始终保持挂载状态。”
Posty.js
import * as React from 'react';
import { Text, View, StyleSheet, Button } from 'react-native';
import {createStackNavigator, createAppContainer} from 'react-navigation';
import PostScreen from './screens/PostScreen';
import NewPostScreen from './screens/NewPostScreen'
// Posty adında komponentimi oluşturdum.
// Bu komponent çağrıldığında bir stack navigator exportlamak istediğim için ana komponent Musical'ımın
// içine PostStack stack navigator komponentimi yerleştirdim.
// Stack navigtor ımın içine screenler tanımladım.
export default class Posty extends React.Component{
render(){
return(
<PostStack />
);
}
}
// Yeni bir stack navigator oluşturdum ve adını PostNavigator koydum.
const PostNavigator = createStackNavigator({
Post: {screen: PostScreen},
NewPost: {screen: NewPostScreen}
});
// PostStack adlı containerımı yarattım ki Posty Component'inin içinde kullanabileyim.
const PostStack = createAppContainer(PostNavigator);
PostScreen.js
import React, { Component } from 'react';
import PostList from '../PostList'
import {TouchableOpacity} from 'react-native';
import Icon from 'react-native-vector-icons/FontAwesome'
import { connect } from 'react-redux';
class PostScreen extends Component {
constructor(props){
super(props)
}
static navigationOptions = ({ navigation: { navigate } }) =>({
headerTitle: 'Posts',
headerRight:<TouchableOpacity onPress={() => navigate('NewPost')}>
<Icon style={{marginRight:15}} size={25} name='pencil' />
</TouchableOpacity>
})
render() {
return (
<PostList></PostList>
);
}
}
const mapStateToProps = state => {
return{
id: state.id
}
}
export default connect(mapStateToProps)(PostScreen);
NewPostScreen.js
import React, {Component} from 'react';
import {TextInput,View,Image,TouchableHighlight,StyleSheet,Text} from 'react-native';
import axios from 'axios';
import {connect} from 'react-redux';
class NewPostScreen extends Component {
constructor(props) {
super(props);
this.state = { text: 'What are you thinking?' };
}
onButtonClicked(){
console.log(this.state.text)
const {navigate} = this.props.navigation
axios.post("http://172.29.193.96:5000/newPost",
{
author_id: this.props.id,
content: this.state.text
}).then(
navigate('Post')
)
}
render() {
console.log("NewPostScreen id: ", this.props.id)
return (
<View>
<View style={{flexDirection:'row'}}>
<Image source={require('../../images/cat.png')}></Image>
<TextInput
style={{height: 100, width:350, textAlign:'auto', fontSize:20, marginTop:30, borderColor: 'gray', borderWidth: 1}}
onChangeText={(text) => this.setState({text})}
placeholder={this.state.text}
/>
</View>
<TouchableHighlight style={[styles.buttonContainer, styles.loginButton]} onPress={this.onButtonClicked.bind(this)}>
<Text style={styles.loginText}>Ekle</Text>
</TouchableHighlight>
</View>
);
}
}
const styles = StyleSheet.create({
buttonContainer: {
height:45,
flexDirection: 'row',
justifyContent: 'center',
alignItems: 'center',
marginTop:20,
marginBottom:30,
marginLeft: 240,
width:150,
borderRadius:30,
},
textContainer: {
flexDirection: 'row',
justifyContent: 'center',
alignItems: 'center',
marginBottom: 15,
width:150,
borderRadius:30
},
loginButton: {
backgroundColor: "#00b5ec",
},
loginText: {
color: 'white',
fontSize: 16
}
})
const mapStateToProps = state => {
return{
id: state.id
}
}
export default connect(mapStateToProps)(NewPostScreen);
那么,我应该在哪种屏幕方法中再次调用我的API调用?
答案 0 :(得分:0)
您必须使用反应生命周期
componentDidMount(){
fetch("https://YOUR_API")
.then(response => response.json())
.then((responseJson)=> {
this.setState({
loading: false,
dataSource: responseJson
})
})
.catch(error=>console.log(error)) //to catch the errors if any
}
您在数据源中获得api结果。
答案 1 :(得分:0)
ItemTemplate