从Angular 8的下拉列表中获取倾斜值

时间:2019-07-02 04:26:33

标签: angular forms drop-down-menu

Am使用前端的Angular 8和后端的Laravel在单页应用程序上工作。我有一个具有输入文本字段和下拉列表的表单。文本输入字段上的值可以在打字稿文件上很好地捕获,但是捕获从下拉列表中选择的值时出现问题,这样我就可以在后端提交了。

〜请协助?

Create.component.html

<form #createForm=ngForm (ngSubmit)="onSubmit()">
    <div class="form-group row">
     <div class="col-sm-6">
        <label for="formGroupExampleInput">Child SurName</label>
        <input 
            type="text" 
            name="childSurName" 
            class="form-control" 
            id="childSurName" 
            placeholder="ChildSurName"
            [(ngModel)]="form.childSurName">
    </div>

    <div class="col-sm-6">
        <label for="child-gender">Child Gender</label>
        <select class="form-control" id="childGender" name="child-gender" required>
        <option value="" selected disabled> Child's Gender</option>
            <option value="Male"> Male</option>
            <option value="Female"> Female </option>
        </select>
    </div>
    </div>

    <div class="form-group row">
        <div class="col-sm-12">
            <button 
                type="submit" 
                class="btn btn-lg btn-success btn-block" 
                [disabled]="!createForm.valid">Save Details </button>
        </div>
    </div>
</form>

Create.component.ts

import { Component, OnInit } from '@angular/core';
import { AuthService } from 'src/app/Services/auth.service';
import { Router } from '@angular/router';
import { AuthCheckService } from 'src/app/Services/auth-check.service';

@Component({
  selector: 'app-create',
  templateUrl: './create.component.html',
  styleUrls: ['./create.component.css']
})

export class CreateComponent implements OnInit {

  public form = {
    childSurName: null,
    child-gender: null
  };

  public error = null;

  constructor(
       private Auth:AuthService,
       private router: Router,
       private AuthCheck : AuthCheckService) 
  { }

   //Submit form data to the backend via a function in he service file
   onSubmit(){
    this.Auth.submitFormData(this.form).subscribe(
      data => console.log(data),
      error => console.log(error)
    );
  }

  ngOnInit() {
  }

}

2 个答案:

答案 0 :(得分:1)

在您的[(ngModel)]元素上似乎缺少

select指令。

答案 1 :(得分:1)

将以下内容添加到<select>

[(ngModel)]="form.childGender"

为了保持一致性,还将表单的键重命名为:

public form = {
   childSurName: null,
   childGender: null
};

这是同样适用的stackblitz。 (请注意,在提交时,仅将表单记录到控制台)