cust_valid

Question

我需要有一个cust_valid“ A”和cust_valid“ I”的客户（每个客户2行）。

select c.cust_first_name || ' ' || c.cust_last_name as customer_name,
c.cust_valid from customers c
join sales s on s.cust_id = c.cust_id
where c.cust_valid like '%A%' or
c.cust_valid like '%I%'
group by  c.cust_first_name, c.cust_last_name, c.cust_credit_limit, c.cust_valid
having sum(s.amount_sold) > c.cust_credit_limit * 500;

我的输出是所有拥有cust_valid的A或I的客户。我只需要输出同时拥有两个（两行）的客户

我尝试使用AND而不是OR，但由于在任何行中我们都没有I或A，因此会给我一个空表。

Answer 1

在查询中使用cte，在group by customer_name中使用cust_valid，这样您就只能在with cte as ( select c.cust_first_name || ' ' || c.cust_last_name as customer_name, c.cust_valid from customers c join sales s on s.cust_id = c.cust_id where c.cust_valid like '%A%' or c.cust_valid like '%I%' group by c.cust_first_name, c.cust_last_name, c.cust_credit_limit, c.cust_valid having sum(s.amount_sold) > c.cust_credit_limit * 500 ) select * from cte where customer_name in ( select customer_name from cte group by customer_name having count(distinct cust_valid) = 2 ) 中获得A和I的客户：

Promise.all

Answer 2

您需要执行SELF_JOIN，还需要从GROUP BY中删除CUST_VALID，因为对于同一位客户而言，它是不同的

SELECT
    C.CUST_FIRST_NAME
    || ' '
    || C.CUST_LAST_NAME AS CUSTOMER_NAME,
    LISTAGG(C.CUST_VALID,',') WITHIN GROUP (ORDER BY C.CUST_VALID) AS CUST_VALID
    -- CUST_VALID IS DIFFERENT FOR SAME CUSTOMERS SO LISTAGG IS USED TO GET ALL THE CUST_VALID
FROM
    CUSTOMERS C
    JOIN SALES S ON S.CUST_ID = C.CUST_ID
    JOIN CUSTOMERS C1 ON (C.<UNIQUE_KEYS> = C1.<UNIQUE_KEYS>)
WHERE
    C.CUST_VALID LIKE '%A%'
    AND C1.CUST_VALID LIKE '%I%' -- CONDTITION IS CHANGED TO C1
GROUP BY
    C.CUST_FIRST_NAME,
    C.CUST_LAST_NAME,
    C.CUST_CREDIT_LIMIT
    --C.CUST_VALID -- Removed it from GROUP BY
HAVING
    SUM(S.AMOUNT_SOLD) > C.CUST_CREDIT_LIMIT * 500;

干杯！

Answer 3

将检查移至HAVING子句和COUNT中，以确保您具有每种行类型之一：

select c.cust_first_name || ' ' || c.cust_last_name as customer_name,
       LISTAGG( c.cust_valid, ',' ) WITHIN GROUP ( ORDER BY c.cust_valid ) AS cust_valid
from   customers c
       join sales s
       on s.cust_id = c.cust_id
WHERE  c.cust_valid like '%A%'
OR     c.cust_valid like '%I%'
group by  c.cust_first_name,
       c.cust_last_name,
       c.cust_credit_limit
having sum(s.amount_sold) > c.cust_credit_limit * 500
AND    COUNT( CASE WHEN c.cust_valid like '%A%' THEN 1 END ) > 0
AND    COUNT( CASE WHEN c.cust_valid like '%I%' THEN 1 END ) > 0;