带参数的计时器对象(python)

时间:2011-04-15 23:47:32

标签: python object timer arguments

如何使用计时器对象在def内的class之间传递参数?

def onrepeat(self,user, arg):
    args = arg.split()
    messagearg = args[0]
    colorarg = args[1]
    if colorarg == "black":
        color = "&0"
    if colorarg == "dark blue" or "darkblue":
        color = "&1"
    if colorarg == "dark green" or "darkgreen":
        color = "&2"
    if colorarg == "dark teal" or "darkteal":
        color = "&3"
    if colorarg == "dark red" or "darkred":
        color = "&4"
    if colorarg == "purple":
        color = "&5"
    if colorarg == "gold":
        color = "&6"
    if colorarg == "gray":
        color = "&7"
    if colorarg == "dark gray" or "darkgrey" or "dark grey" or "darkgrey":
        color = "&8"
    if colorarg == "blue":
        color = "&9"
    if colorarg == "bright green" or "brightgreen":
        color = "&a"
    if colorarg == "teal":
        color = "&b"
    if colorarg == "red":
        color = "&c"
    if colorarg == "pink":
        color = "&d"
    if colorarg == "yellow":
        color = "&e"
    if colorarg == "white":
        color = "&f"
    if colorarg == "":
        color = "&f"
    self.timerobj = Timer(3.0, self.repeat2)
    self.timerobj.start()

def repeat2(self,messagearg,color):
    self.bot.sendMessage(color + messagearg)

这会给我一个错误说:

repeat2 needs 3 arguments while only 2 are given.

为了解决这个问题,我改变了

self.timerobj = Timer(3.0, self.repeat2) 

self.timerobj = Timer(3.0, self.repeat2(messagearg,color))

但这也不起作用!

1 个答案:

答案 0 :(得分:-1)

计时器具有以下签名

class threading.Timer(interval, function, args=[], kwargs={})

请注意,它接受argskwargs。所以你只需要提到它们就可以将你的args发送到Timer函数。试试这个:

Timer(3.0, self.repeat2,messagearg,color)