Question

我有输入电话的报告。我想获取列%Weekdays的总和。例如，我将向您展示我的价值观和预期结果：预期的结果是100,7％

这是我的％weekdays（平均值）代码，但我希望所有行的总值：

 =avg(IIF(Weekday(Fields!DATE_YYYYMMDD.Value,2)<6,CDBL(Fields!N_ENTERED.Value),Nothing))/
iif(Sum(IIF(Weekday(Fields!DATE_YYYYMMDD.Value,2)<6, CDBL(Fields!N_ENTERED.Value), Nothing),"PRESENTATION_NAME")=0,1   
    (Sum(IIF(Weekday(Fields!DATE_YYYYMMDD.Value,2)<6, CDBL(Fields!N_ENTERED.Value), Nothing),"PRESENTATION_NAME")/
iif(code.getWeekDaysCount(Parameters!From_date.Value,Parameters!To_date.Value)=0,1,code.getWeekDaysCount(Parameters!From_date.Value, Parameters!To_date.Value))))

Answer 1

如果您只想汇总“％工作日”列，并假设其为myWeekdaysCol，则可以这样做

=SUM(ReportItems!myWeekdaysCol.Value)

这将简单地将最终结果求和，而不必创建一个难以理解的长表达式。

Answer 2

这是我简化您的数据并生成总和的

％工作日只是=Fields!Weekday.Value/10.40

然后我刚刚在Group-below下创建了％dayday的总和

并简单地生成总和

=Sum(Fields!Weekday.Value/10.40)

在我简化的情况下，我生成＆weekday除以10.40，这就是我的公式。您将必须执行以下操作

=Sum(avg(IIF(Weekday(Fields!DATE_YYYYMMDD.Value,2)<6,CDBL(Fields!N_ENTERED.Value),Nothing))/
iif(Sum(IIF(Weekday(Fields!DATE_YYYYMMDD.Value,2)<6, CDBL(Fields!N_ENTERED.Value), Nothing),"PRESENTATION_NAME")=0,1   
    (Sum(IIF(Weekday(Fields!DATE_YYYYMMDD.Value,2)<6, CDBL(Fields!N_ENTERED.Value), Nothing),"PRESENTATION_NAME")/
iif(code.getWeekDaysCount(Parameters!From_date.Value,Parameters!To_date.Value)=0,1,code.getWeekDaysCount(Parameters!From_date.Value, Parameters!To_date.Value)))))

如何在我的报告中获得针对已输入呼叫的总正确结果？

2 个答案: