Question

myfile=open("output_log.text", "r")
for file in myfile:
    count = 0
    for word in file:
        if word == "Jenkins":
            count = count + 1
        return word
print(int(word))

上面的编码产生了语法错误，我在上面的标题中提到过。有谁能帮助我解决这个问题？感谢大家。

Answer 1

return语句应在函数/方法内使用。您尚未定义一个，因此return的使用是不正确的。您应该打印单词而不是使用return。另外，您正在打开文件而不是关闭它。我建议使用with语句。

with open("output_log.text", "r") as myfile:
    for file in myfile:
        count = 0
        for word in file:
            if word == "Jenkins":
                count = count + 1
print(int(word))

最有可能我认为您正在尝试打印"Jenkins"在文件中显示的次数。然后您要打印count。 file的名称也不合适，因为您正在读取文件的行而不是文件的文件。像这样

line

注意：可以使用def count_word_in_file(filename, keyword): count = 0 with open(filename, "r") as file: for line in file: for word in line.split(): if word == keyword: count += 1 return count count = count_word_in_file("output_log.text", "Jenkins") print(count)方法BTW来轻松完成此操作。

str.count

Answer 2

OK, you have not defined a function yet. :-)  

####### Beginning of python script #######

def myfunc(myword, myfile):
    # rest of your function code.
    for file in myfile:
        count = 0
        for word in file:
            if word == myword:
                count = count + 1
    return myword, count  

# Now call the function from outside.
# Set myfile and myword variables.
myfile = open(r'c:\python\so\output_log.text', "r")
myword = 'Jenkins'
results = myfunc(myword, myfile)

print(results)
# Example print output.
> ('Jenkins', 4) 

# You are passing myfile and myword as variables in your function call.
# You can changes these later for a different file and a different word.

SyntaxError：在注释中生成“返回”外部函数

2 个答案: