我一直在bash中创建curl,在这里我想使用调用函数save_log()
保存到日志文件中,但是当我打开txt文件时,它只是告诉我执行于仅标题代码和响应正文为空白(空)
这是我的脚本:
SECRET_KEY='lolz'
FILE_NAME="test.txt"
function save_log()
{
printf '%s\n' \
"Header Code : $1" \
"Executed at : $(date)" \
"Response Body : $2" \
"====================================================================================================="$'\r\n\n' >> output.log
}
# while IFS= read -r line; do
while IFS= read -r line || [[ -n "$line" ]];
do
HTTP_RESPONSE=$(curl -L -w "HTTPSTATUS:%{http_code}" -H "X-Gitlab-Event: Push Hook" -H 'X-Gitlab-Token: '$SECRET_KEY --insecure $line 2>&1) &
HTTP_BODY=$(echo $HTTP_RESPONSE | sed -e 's/HTTPSTATUS\:.*//g') &
HTTP_STATUS=$(echo $HTTP_RESPONSE | tr -d '\n' | sed -e 's/.*HTTPSTATUS://') &
echo $HTTP_RESPONSE
save_log "$HTTP_STATUS" "$HTTP_BODY" &
done < $FILE_NAME
这是输出
Header Code :
Executed at : Mon Jul 1 07:01:40 WIB 2019
Response Body :
=====================================================================================================
有人可以帮助我吗?
答案 0 :(得分:3)
只需删除控制操作符 &
,即可强制您的命令在后台运行,并且与您自己的脚本控制流异步运行。
这将导致不带任何参数地调用您的save_log()
函数(因为它们在后台,并且在您调用save_log()
时甚至没有完成)。
我进行了测试,并且可以正常工作(我不知道FILE_NAME上有哪些URL,因此我只添加了一些随机URL)
SECRET_KEY='lolz'
FILE_NAME="test.txt"
function save_log()
{
printf '%s\n' \
"Header Code : $1" \
"Executed at : $(date)" \
"Response Body : $2" \
"====================================================================================================="$'\r\n\n' >> output.log
}
# while IFS= read -r line; do
while IFS= read -r line || [[ -n "$line" ]];
do
HTTP_RESPONSE=$(curl -L -w "HTTPSTATUS:%{http_code}" -H "X-Gitlab-Event: Push Hook" -H 'X-Gitlab-Token: '$SECRET_KEY --insecure $line 2>&1)
HTTP_BODY=$(echo $HTTP_RESPONSE | sed -e 's/HTTPSTATUS\:.*//g')
HTTP_STATUS=$(echo $HTTP_RESPONSE | tr -d '\n' | sed -e 's/.*HTTPSTATUS://')
echo $HTTP_RESPONSE
save_log "$HTTP_STATUS" "$HTTP_BODY"
done < $FILE_NAME
输出:
Header Code : 200
Executed at : Sun Jun 30 18:05:12 UTC 2019
Response Body : <!DOCTYPE html> (...)