Question

[0, 1, 2, 3],[4, 5, 6, 7, 8],[9, 10, 11],[12, 13, 14, 15],[16, 17, 18, 19, 20],[21, 22, 23]
[0, 1, 2],[3, 4, 5],[6, 7, 8, 9],[10, 11, 12, 13]

[0, 1],[2],[3, 4, 5],[6, 7, 8, 9]
[0, 1, 2, 3],[4, 5, 6, 7],[8],[9, 10, 11, 12],[13, 14, 15]

我有上面的文本文件。问题是该文件中的每个索引都是一个字符串，但是我想将它们转换回整数。我尝试过：

with open("abc.txt", "r") as text_file:
    new_list = [int(line) for line in text_file]

我收到此错误：

ValueError: invalid literal for int() with base 10: '[0, 1, 2, 3],[4, 5, 6, 7, 8],[9, 10, 11],[12, 13, 14, 15],[16, 17, 18, 19, 20],[21, 22, 23]\n'

输出-

[0, 1, 2, 3],[4, 5, 6, 7, 8],[9, 10, 11],[12, 13, 14, 15],[16, 17, 18, 19, 20],[21, 22, 23]
[0, 1, 2],[3, 4, 5],[6, 7, 8, 9],[10, 11, 12, 13]

[0, 1],[2],[3, 4, 5],[6, 7, 8, 9]
[0, 1, 2, 3],[4, 5, 6, 7],[8],[9, 10, 11, 12],[13, 14, 15]

所有这些行都代表包含INTEGERS的列表。

Answer 1

了解有关ast.literal_eval

的信息

尝试一下

import ast
with open("abc.txt", "r") as text_file:
    new_list = [list(ast.literal_eval(line)) for line in text_file if line.strip()]

输出：

[[[0, 1, 2, 3],  [4, 5, 6, 7, 8],  [9, 10, 11],  [12, 13, 14, 15],  [16, 17, 18, 19, 20],  [21, 22, 23]],
 [[0, 1, 2], [3, 4, 5], [6, 7, 8, 9], [10, 11, 12, 13]],
 [[0, 1], [2], [3, 4, 5], [6, 7, 8, 9]],
 [[0, 1, 2, 3], [4, 5, 6, 7], [8], [9, 10, 11, 12], [13, 14, 15]]]

Answer 2

您可以使用literal_eval和chain：

from ast import literal_eval
from itertools import chain

with open("abc.txt", "r") as text_file:
    new_lines = (list(literal_eval(line)) for line in text_file if line.strip())
    new_list = list(chain(*new_lines))

line.strip()是跳过空行。

Answer 3

正则表达式是您最好的选择，

for i in range(len(z)): 
    new_z[i] = int(z[i])

然后剩下的就是将列表中的每个字符串转换为整数，这是一个简单的示例，

remove

覆盖字符串从文本文件到整数

3 个答案: