Question

在我尝试使用“ firebase.auth（）。createUserWithEmailAndPassword（）;”后，我收到“ xhrio.js：632 POST https://www.googleapis.com/identitytoolkit/v3/relyingparty/signupNewUser?key=AIzaSyCsoN9mw6k7qmqdw_-yejEd_tvjjtrqqfk 400”消息。

为什么？我该如何欺骗它？

我的index.html：

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <meta http-equiv="X-UA-Compatible" content="ie=edge">
    <title>Document</title>
</head>
<body>
    <div class="conatiner">
        <input type="text" id="email" placeholder="email..."/>
        <input type="text" id="password" placeholder="password..."/>
        <button onclick="sing_In()">Sing In</button>
        <button onclick="sing_Up()">Sing Up</button>
        <button onclick="sing_Out()">Sing Out</button>

    </div>

    <!-- The core Firebase JS SDK is always required and must be listed first -->
    <script src="https://www.gstatic.com/firebasejs/6.2.4/firebase-app.js"></script>
    <script src="https://www.gstatic.com/firebasejs/6.2.4/firebase-auth.js"></script>

     <script>
      // Your web app's Firebase configuration
      var firebaseConfig = {
        apiKey: "AIzaSyCsoN9mw6k7qmqdw_-yejEd_tvjjtrqqfk",
        authDomain: "auth-1362e.firebaseapp.com",
        databaseURL: "https://auth-1362e.firebaseio.com",
        projectId: "auth-1362e",
        storageBucket: "",
        messagingSenderId: "765916790727",
        appId: "1:765916790727:web:275006f41a04ad33"
    };
      // Initialize Firebase
      firebase.initializeApp(firebaseConfig);
    </script>
    <script src="app.js"></script>
</body>
</html>

我的app.js：

function sing_Up(){
    firebase.auth().createUserWithEmailAndPassword(document.getElementById("email").value, document.getElementById("password").value).catch(function(error) {
        // Handle Errors here.
        var errorCode = error.code;
        var errorMessage = error.message;
        // ...
      });
}

function sing_In(){
  firebase.auth().signInWithEmailAndPassword(document.getElementById("email").value, document.getElementById("password").value).catch(function(error) {
    // Handle Errors here.
    var errorCode = error.code;
    var errorMessage = error.message;
    // ...
  });

}

  function sign_Out(){
    firebase.auth().signOut().then(function() {
        // Sign-out successful.
      }).catch(function(error) {
        // An error happened.
      });
  }

是什么原因导致POST 400？我该如何欺骗它？

0 个答案: