Question

{'00': ['000011110000111111110000',
        '000011110000111111110000',
        '000011110000111111110000',
        '000010000000111000000000',
        '111110000111111000000111',
        '111110000111111000000111',
        '111110000111111000000111',
        '111001111111111000000111',
        '000001110000000000000111',
        '000011110000000011111111',
        '000011110000000011111111',
        '000011110000000011111111',
        '111111110000000011110000',
        '111111110000000011110000',
        '111111110000000011110000',
        '111000000000000010000000',
        '111000000111111110000111',
        '111000000111111110000111',
        '111000000111111110000111',
        '111000000111111001111111',
        '000000000111000001110000',
        '000011111111000011110000',
        '000011111111000011110000',
        '000011111111000011110000'],
 '01': ['01111111000000',
        '01111111000000',
        '01111111000000',
        '01110000000000',
        '01110000000000',
        '01110000000000',
        '11110000000111',
        '11110000000111',
        '11110000000111',
        '00000000000111',
        '00000111111111'],
 '02': ['0000111100',
        '0000111000',
        '1111111001',
        '0000000111',
        '0000000111',
        '0000000111',
        '0010000100',
        '0001000100',
        '0000000100',
        '0000000100']}

我有一个看起来像这样的文本文件。我希望输出文件仅从字典中提取值并将它们写入另一个数组中，而且其顺序应与现在出现的顺序相同。因此，应首先显示00数组，然后显示01,02，依此类推。输出为00-

['000011110000111111110000','000011110000111111110000','000011110000111111110000','000010000000111000000000','111110000111111000000111','111110000111111000000111','111110000111111000000111','111001111111111000000111','000001110000000000000111','000011110000000011111111','000011110000000011111111','000011110000000011111111','111111110000000011110000','111111110000000011110000','111111110000000011110000','111000000000000010000000','111000000111111110000111','111000000111111110000111','111000000111111110000111','111000000111111001111111','000000000111000001110000']

01-

的输出

['01111111000000','01111111000000','01111111000000','01110000000000', '01110000000000','01110000000000','11110000000111','11110000000111','11110000000111', '00000000000111','00000111111111']

我尝试使用json解决此问题，但显然每个元素都是一个列表，并且不起作用。

Answer 1

我很惊讶Python的sample.json模块对您不起作用，因此我将您的输入存储在名为'的文件中并亲自尝试。

问题是您的json格式未达到Python期望的格式。它使用单引号（"）代替双引号（json）来分隔字符串。在我的文本编辑器中打开文件并将所有单引号替换为双引号之后，Python3的>>> import json >>> with open('./sample.json', 'r') as jfile: j = json.load(jfile) >>> j['02'] ['0000111100', '0000111000', '1111111001', '0000000111', 00000111', '0000000111', '0010000100', '0001000100', '0000000100', 000000100']模块对我来说就很好了。这是我的Python Shell会话：

output.json

现在我可以打开输出文件（>>> with open('./output.json', 'w') as outfile: outfile.write(str(j['01'])) # Remember to convert the list to a string! 198）并将其列表写入其中。

$ cat output.json
['01111111000000', '01111111000000', '01111111000000', '01110000000000', 
'01110000000000', '01110000000000', '11110000000111', '11110000000111', 
'11110000000111', '00000000000111', '00000111111111']

退出python shell之后，列表就在它所属的位置：

json

也许您现在想给{{1}}模块一个机会？当然，它的输入有些挑剔。但是，一旦您满意，与手工切片和切块相比，它将使您的数据处理工作变得更加清晰，简单和不易出错。

将字符串列表从文本文件转换为int数组

1 个答案: