Question

我正在使用PHP来计算单个电子邮件中有多少个附件的值。

当我尝试这样做时：

echo count($structure->parts);

输出将显示如下：

我在一封电子邮件中有2个附件，因此输出返回不正确。所以当我尝试这个：

for($i = 0; $i < count($structure->parts); $i++) {
    echo $i;
}

输出返回如下：

这是完整的代码：

<?php

require_once "Mail.php";
require_once('Mail/IMAPv2.php');

$username = 'myusername';
$password = 'mypassword';
$mailserver = '{imap.domain.com:993/imap/ssl/novalidate-cert}INBOX';
$mailbox = imap_open($mailserver, $username, $password) or die("Can't connect: " . imap_last_error());
$key = "mykey";
$email_number = openssl_decrypt(hex2bin('274'),'AES-128-CBC', $key);
$attach_id = $_GET['attid'];

/* get information specific to this email */
$overview = imap_fetch_overview($mailbox, $email_number, 0);

$message = imap_fetchbody($mailbox, $email_number, 2);

/* get mail structure */
$structure = imap_fetchstructure($mailbox, $email_number);
$attachments = array();


for($i = 0; $i < count($structure->parts); $i++) {
    echo $i;
}
?>

我在一封电子邮件中有2个附件，所以返回的输出应显示2个而不是3或012，但仍显示3个。我试图在google上找到如何计数的答案使用imap的一封电子邮件中附件的值，但我无法这样做。

您能给我一个例子来说明如何计算一封电子邮件中有多少个附件吗？

谢谢。

编辑：这是$ structure-> parts的输出：

Array ( [0] => stdClass Object ( [type] => 1 [encoding] => 0 [ifsubtype] => 1 [subtype] => 
ALTERNATIVE [ifdescription] => 0 [ifid] => 0 [ifdisposition] => 0 [ifdparameters] => 0 
[ifparameters] => 1 [parameters] => Array ( [0] => stdClass Object ( [attribute] => boundary 
[value] => 00000000000014af61058c780612 ) ) [parts] => Array ( [0] => stdClass Object ( [type] => 0 
[encoding] => 0 [ifsubtype] => 1 [subtype] => PLAIN [ifdescription] => 0 [ifid] => 0 [lines] => 3 
[bytes] => 42 [ifdisposition] => 0 [ifdparameters] => 0 [ifparameters] => 1 [parameters] => 
Array ( [0] => stdClass Object ( [attribute] => charset [value] => UTF-8 ) ) ) [1] => 
stdClass Object ( [type] => 0 [encoding] => 4 [ifsubtype] => 1 [subtype] => HTML [ifdescription] => 0 
[ifid] => 0 [lines] => 4 
[bytes] => 307 [ifdisposition] => 0 [ifdparameters] => 0 [ifparameters] => 1 [parameters] => 
Array ( [0] => stdClass Object ( [attribute] => charset [value] => UTF-8 ) ) ) ) ) [1] => 
stdClass Object ( [type] => 3 [encoding] => 3 [ifsubtype] => 1 [subtype] => OCTET-STREAM 
[ifdescription] => 0 [ifid] => 1 [id] => [bytes] => 99376 [ifdisposition] => 1 [disposition] => 
attachment [ifdparameters] => 1 [dparameters] => Array ( [0] => stdClass Object ( [attribute] => 
filename [value] => 2019-01-23 (1).rar ) ) [ifparameters] => 1 [parameters] => Array ( [0] => 
stdClass Object ( [attribute] => name [value] => 2019-01-23 (1).rar ) ) ) [2] => stdClass Object 
( [type] => 3 [encoding] => 3 [ifsubtype] => 1 [subtype] => X-ZIP-COMPRESSED [ifdescription] => 0 
[ifid] => 1 [id] => [bytes] => 250846 [ifdisposition] => 1 [disposition] => attachment 
[ifdparameters] => 1 [dparameters] => Array ( [0] => stdClass Object ( [attribute] => filename 
[value] => email.zip ) ) [ifparameters] => 1 [parameters] => Array ( [0] => 
stdClass Object ( [attribute] => name [value] => email.zip ) ) ) )

Answer 1

请仔细查看$structure->parts的内容。您有3个部分组成的数组，其中最后两个部分包含以下属性：

[ifdisposition] => 1 
[disposition] => attachment

由于第一部分包含[ifdisposition] => 0并且[disposition]属性不存在，我们可以推断出ifdisposition是一个布尔值，它告诉您disposition是否可用。我们可以通过检查PHP documentation for imap_fetchstructure()来验证这一点。

要查找所有附件，您应遍历各部分并匹配ifdisposition === true和disposition === 'attachment'的所有情况。如果要快速提取所有这些内容，可以执行以下操作：

$attachments = array_filter($structure->parts, function($part) {
    return $part->ifdisposition && $part->disposition === 'attachment';
});

php依靠一封电子邮件中的附件数量

1 个答案: