Question

我在熊猫数据框中有一个“地址”列。我需要在python中将序数转换为第一个到第一个，第二个到第二个，等等。我尝试搜索解决方案，但没有成功。

我的数据框如下所示：-

print(newdf) :- 
Address 
0 2 fairgreen lane bolton callan 
1 2 leix rd cabra dublin 7 
2 7 sraid na mara 1st sea rd strandhill rd 

Suppose the 3rd record has 1st sea road, it should be converted to first sea road. I am not sure how to pass the data frame column in the argument.

```python
The below code converts number to word. 
 num2words(42, to='ordinal') 'forty-second'  num2words(42, to='cardinal') 'forty-two'

Answer 1

这是一个很好的软件包，您可以将其pip安装到项目中，该项目会将序数转换为单词https://pypi.org/project/num2words/，此处的文档提供了许多有关如何使用它的良好信息。

Answer 2

您可以从字符串中提取数字（即从42中提取42nd，然后将num2words与ordinal=True一起使用：

import re
from num2words import num2words

ordinalAsNumber = "42nd"
number = re.search('\d+', ordinalAsNumber)

ordinalAsString = num2words(number[0], ordinal=True)

print( ordinalAsString ) # forty-second

您可以像这样从字符串中提取所有序数：

text = "Text with several ordinals such as 42nd, 31st, and 5th as well as plain numbers such as 1, 2, 3."
numbers = re.findall('(\d+)[st|nd|rd|th]', text)

for n in numbers:
     ordinalAsString = num2words(n, ordinal=True)
     print( ordinalAsString )

输出：

forty-second
thirty-first
fifth

您可以用re.sub()进行替换：

text = "Text with several ordinals such as 42nd, 31st, and 5th as well as plain numbers such as 1, 2, 3."
numbers = re.findall('(\d+)[st|nd|rd|th]', text)

newText = text
for n in numbers:
     ordinalAsString = num2words(n, ordinal=True)
     newText=re.sub(r"\d+[st|nd|rd|th]", ordinalAsString, text, 1)

print ( text )
print( newText )

输出：

# Text with several ordinals such as 42nd, 31st, and 5th as well as plain numbers such as 1, 2, 3.
# Text with several ordinals such as forty-secondd, thirty-firstt, and fifthh as well as plain numbers such as 1, 2, 3.

是否有python函数将序数转换为word

2 个答案: